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34kurt
3 years ago
12

Which of the following statements provide evidence to support the big bang theory? Select the two correct answers. i need help p

lease!
Chemistry
1 answer:
Leona [35]3 years ago
8 0

Answer:

See explaination

Explanation:

CBR (Cosmic Background Radiation)-

Uniform energy that is heard everywhere in the universe. It supports the Big Bang Theory because we can assume that it also started in the same place.

Hubble's Law-

Hubble's Law states that the planets are getting farther away from eachother, therefore, the universe is expanding and must have started as a smaller piece.

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Which of the following methods can be used to completely separate a solution containing alcohol and water?
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A only gets out some of it but not all
C that isn't for alcaholl
D I don't think that even exists
B is the only correct answer
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4 years ago
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Give 7 and example of how each wave in the EM spectrum in used in our daily lives
bogdanovich [222]
1. it’s use for our food in like microwaves and ovens
2. airplanes are guided by radar waves,
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8 0
3 years ago
In the first 15.0 s of the reaction, 1.9×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.480 L . What is the
N76 [4]

The question is incomplete, here is the complete question:

Consider the following reaction:  2N_2O(g)\rightarrow 2N_2(g)+O_2(g)

In the first 15.0 s of the reaction, 1.9×10⁻² mol of O₂ is produced in a reaction vessel with a volume of 0.480 L . What is the average rate of the reaction over this time interval?

<u>Answer:</u> The average rate of appearance of oxygen gas is 2.64\times 10^{-3}M/s

<u>Explanation:</u>

We are given:

Moles of oxygen gas = 1.9\times 10^{-2}moles

Volume of solution = 0.480 L

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

So, \text{Molarity of }O_2=\frac{1.9\times 10^{-2}mol}{0.480L}=0.0396M

The given chemical reaction follows:

2N_2O(g)\rightarrow 2N_2(g)+O_2(g)

The average rate of the reaction for appearance of O_2 is given as:

\text{Average rate of appearance of }O_2=\frac{\Delta [O_2]}{\Delta t}

Or,

\text{Average rate of appearance of }O_2=\frac{C_2-C_1}{t_2-t_1}

where,

C_2 = final concentration of oxygen gas = 0.0396 M

C_1 = initial concentration of oxygen gas = 0 M

t_2 = final time = 15.0 s

t_1 = initial time = 0 s

Putting values in above equation, we get:

\text{Average rate of appearance of }O_2=\frac{0.0396-0}{15-0}\\\\\text{Average rate of appearance of }O_2=2.64\times 10^{-3}M/s

Hence, the average rate of appearance of oxygen gas is 2.64\times 10^{-3}M/s

8 0
4 years ago
If a hydrocarbon molecule contains a triple bond, its chemical name ends in
murzikaleks [220]
-yne. Hope this helps.
4 0
3 years ago
Earth has an __of about 30 percent, reflecting much of the sun's radiation<br> back into space.
Aleksandr [31]

Answer: Albedo

Explanation:

((Earth's normal albedo is about 0.3.)))

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3 0
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