Draw the structure of a compound with the molecular formula C9H10O2 that exhibits the following spectral data. (a) IR: 3005 cm-1
, 1676 cm-1, 1603 cm-1 (b) 1H NMR: 2.6 ppm (singlet, I
1 answer:
Answer:
The answer is 3-Phenylpropanoic acid (see attached structure)
Explanation:
From spectral data:
3005 cm-1 ⇒ carboxylic acid (broad band)
1670 cm-1 ⇒ C=C
1603 cm-1 ⇒ Aromatic C-C bond
H NMR frequency at 2.6 ppm, singlet, ⇒ OH with no surrounding protons, possible deshielding (clearer investigation of spectrum would be expedient).
Hence, our C9H10O2 compound has an aromatic ring and carboxylic acid group attached to it.
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Answer:
99.3%
Explanation:
The percent by mass of the solute can be expressed as:
- % mass =
* 100%
And for this problem:
- Mass of Solute = Mass of sodium lithium chloride = 29 g
- Mass of Solvent = Mass of Water
So to calculate the percent by mass first we need to <u>calculate the mass of water</u>, to do so we use its<em> density</em> (1 g/L):
- 202 mL is equal to (202/1000) 0.202 L.
Density water = mass water / volume
- 1 g/L = mass water / 0.202 L
- Mass water = 0.202 g
Now we have all the data required to <u>calculate the % mass:</u>
- % mass =
* 100 % = 99.3%