Draw the structure of a compound with the molecular formula C9H10O2 that exhibits the following spectral data. (a) IR: 3005 cm-1
, 1676 cm-1, 1603 cm-1 (b) 1H NMR: 2.6 ppm (singlet, I
1 answer:
Answer:
The answer is 3-Phenylpropanoic acid (see attached structure)
Explanation:
From spectral data:
3005 cm-1 ⇒ carboxylic acid (broad band)
1670 cm-1 ⇒ C=C
1603 cm-1 ⇒ Aromatic C-C bond
H NMR frequency at 2.6 ppm, singlet, ⇒ OH with no surrounding protons, possible deshielding (clearer investigation of spectrum would be expedient).
Hence, our C9H10O2 compound has an aromatic ring and carboxylic acid group attached to it.
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<h2>14.50 cm³</h2>Explanation:
The volume of a substance when given the density and mass can be found by using the formula
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density = 7.86 g/cm³
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<h3>14.50 cm³</h3>Hope this helps you