The tension in the string and the acceleration must be equal for both masses. (See the free body diagrams)
1) 1025km per 13.5hr = 1025km/13.5hr = 75.9 km/hr
2) 400km per 30min = 400km/30min = 13.3 km/min
13.3km/min X (60min per hr) = 13.3km/min(60min/hr) = 800km/hr
3) 45km/hr in 40min = 45km/hr X 40min X (1hr/60min) = 30km.
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4) (30m/s - 10m/s) per 10s = 20m/s/10s = 2ms/s = 2m/s/s = 2m/s^2 </span>
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<span>The lowest point in Death Valley is 85 m below sea level. The summit of nearby Mt. Whitney has an elevation of 4420 m. </span>
Answer:
The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is
8.00 x 10-13J
Explanation:
In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).
Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)
Although, the kinetic energy is converted to potential energy in Coulomb's law equation.
That is,
1/2(mv^2) = (K* q1q2)/r
Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter
