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MissTica
3 years ago
10

How many weeks are in the regular NFL season?

Physics
2 answers:
Virty [35]3 years ago
7 0
B. 18 though now I believe it’s 17
natita [175]3 years ago
7 0

Answer:

The answer is E, 17 weeks

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What is the summary for Electrons and protons​
alina1380 [7]

Explanation:

the link enjoy

3 0
3 years ago
A dentist’s drill starts from rest. After 1.46 sof constant angular acceleration, it turns at arate of 27000 rev/min.Find the dr
Black_prince [1.1K]

Answer:

616.3 rad/s²

Explanation:

Given that

t= 1.46 s

Initial angular velocity ,ωi = 0 rad/s

Final angular velocity ωf= 27000 rev/min

Angular speed in the rad/s given as

\omega_f=\dfrac{2\pi N}{60}\ rad/s

Now by putting the values

\omega_f=\dfrac{2\times 27000}{60}\ rad/s

ωf=900 rad/s

We know that (if acceleration is constant)

ωf=ωi + α t

α=Angular acceleration

900 = 0 + α x 1.46

\alpha=\dfrac{900}{1.46}\ rad/s^2\\\alpha=616.43\ rad/s^2

Therefore the acceleration will be 616.3 rad/s²  

4 0
4 years ago
How long does creatine phosphate provide every
Tems11 [23]
Creatine phosphate can supply the energy needs of a working muscle at a very high rate, but only for about 8–10 seconds.
6 0
3 years ago
An athlete runs 200 m by running 100 m in a straight line and then turning around and running 100m back to the start point.
siniylev [52]

Answer:

o

Explanation:

The athlete ran a total distance of zero because they ran 100m forward then turned around so they went back to their starting position

6 0
3 years ago
I need help in my physics class and show me how it’s done
Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)

Where | A | is the magnitude of the vector and \alpha is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle \alpha.

Vector A is in the 4th quadrant

So:

A_x = 6\\\\A_y = -6.5

So:

|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846

So:

Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)

\alpha = -47.28 ° +360° = 313 °

\alpha = 313 °

Option 4.

4 0
3 years ago
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