Question

For what value(s) of the constant b does the equation f(x)=3x^2+bx+27 have 1 x-intercept

Answer 1

Step-by-step explanation:

An a quadratic equation,

${ax}^{2} + bx + c = 0$

If the quadratic has one solution,

then

$b {}^{2} - 4ac = 0$

So plug in 27 for c, and 3 for a

${b}^{2} - 4(3)(27) = 0$

${b}^{2} - 324 = 0$

${b}^{2} = 324$

$b = 18$

or

$b = - 18$

So our answer is 18 or -18