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2 years ago

How much work do I put in if I pushed an object with a force of 64 a distance of 11m

Physics

1 answer:

miv72 [106K]2 years ago

5 0

Answer:

Work = Force * Distance

Here,

force = 64 N
distance = 11m

Thus, Work = 64 * 11 = 704 joules(J)

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A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.2

leva [86]

Answer:

Tension = 0.012 N

Explanation:

If the black widow spider is hanging vertically motionless from the ceiling above. Then, the weight of the spider must be balancing the tension in the spider web. Therefore,

Tension = Weight

Tension = mg

where,

m = mass of spider = 1.27 g = 0.00127 kg

g = acceleration due to gravity = 9.8 m/s²

Therefore,

Tension = (0.00127 kg)(9.8 m/s²)

<u>Tension = 0.012 N</u>

8 0

3 years ago

One litre of crude oil weighs 9.6N. Calculate its specific weight, density and specific gravity.

Zepler [3.9K]

Answer:

The answer is " $\bold{9600 \frac{N}{m^3}, 978.59 \frac{kg}{m^3}, and \ 0.978}$ "

Explanation:

Given:

$\to v=1\ liter= 10^{-3} \ m^3\\\\\to w= 9.6 \ N\\$

calculation:

$Specific \ weight =\frac{w}{v}=\frac{9.6}{10^{-3}}=9600 \frac{N}{m^3} \\\\w=mg\\\\m= \frac{w}{g}=\frac{9.6}{9.81}=0.9785\ kg\\\\\rho\ (density)=\frac{m}{v}=\frac{0.9785}{10^{-3}}=978.59 \frac{kg}{m^3}\\\\specific \ gravity = \frac{\prho \ obj}{\rho w}=\frac{978.54}{1000}=0.978$

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3 years ago

No matter how well we get along with our parents as adolescents, there comes a time when we need to break away and assert our ow

KonstantinChe [14]

Answer: I never said anything to them but if i did it would be "I need a break from you, i love you but sometimes I have to find the path on my own." i would say this if i wasn't scared to hurt them.

Explanation:

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3 years ago

Pure water is a(n) _____.

Mashutka [201]

The correct answer would be compound

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3 years ago

A child is sledding. He starts at the top of the hill with a velocity of zero, and 3 seconds later he is speeding down the hill

Flauer [41]

Magnitude of acceleration = (change of speed) / (time for the change) =

(12 m/s - 0) / (3 sec) =

12/3 = <em>4 m/s²</em>

What's a challenge question ? Have we all passed the event horizon
and been spaghettified without knowing it ?

8 0

3 years ago