Since the speed of sound is very high, we consider the time period of thunder and lightening negligible.
Now, d = vt
thus, d = 343 x 16.2
thus, d = 5556.6 metres
Thus, we are 5556.6 metres away from lightening ( approximately)
Answer: 8.43 m
Explanation:
Given
Mass of the rocket, m = 600 g = 0.6 kg
Speed of riling, v = 2.5 m/s
F = mg, where
F = weight of the rocket in N
m = mass of the rocket in kg
g = acceleration due to gravity in m/s²
F = 0.6 * 9.8
F = 5.88 N
Since the the vertical thrust on the rocket is 8 N and 5.88 N of it will be used to counter the rockets weight. Thus, the remaining 2.12 N is what is available to provide acceleration.
Upward acceleration of the rocket is..... F = ma, a = F / m
a = 2.12 / 0.6
a = 3.53 m/s²
using equation of motion, we will calculate how long it will take to rise 20 m in the air
S = ut + 1/2at², where u = 0
20 = 1/2 * 3.53 * t²
t² = 4. / 3.53
t² = 11.33
t = √11.33 = 3.37 s
The distance then is
v = Δx / t, such that
Δx = v * t
Δx = 2.5 * 3.37
Δx = 8.43 m
Answer:
Work done by friction along the motion is given as
Explanation:
As per work energy theorem we can say
Work done by all forces = change in kinetic energy of the system
so here car is moving from bottom to top
so here the change in kinetic energy is total work done on the car
so here we will have
now plug in all data in it
Chemical sedimentary rocks are formed through evaporation and precipitation of minerals in solution.
For instance, travertine limestone, gypsum, or halite (salt).
