At equilibrium the concentrations of:
[HSO₄⁻] = 0.10 M;
[SO₄²⁻] = 0.037 M;
[H⁺] = 0.037 M;
There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.
HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid. HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.
R 
⇄ 
I 
C 
E 
× 
for 
. As a result,
![\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%2B%5D.%20%5BSO_4%5E2%5E-%5D%7D%7BHSO_4%5E-%7D%20%3D%20K_a)
is large. It is no longer valid to approximate that ![[HSO^-_4]](https://tex.z-dn.net/?f=%5BHSO%5E-_4%5D)
at equilibrium is the same as its initial value.
× 
× 
Solving the quadratic equation for 
since represents a concentration;
Then, round the results to 2 significant figure;
Learn more about concentration here:
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The five basic types of chemical reactions are combination, decomposition, single
replacement, double replacement, and combustion.
C. Thermosphere is the correct answer
Answer:
Explanation:
There are some radioactive nuclides can be used to measure time on an archeological scale. One is the best example of this is radiocarbon dating. This process is based on the ratio of caebon-14 to carbon-12 in the atmosphere which is relatively constant.
The half time of C-14 5730 years
Carbon-14 is a radioactive nucleus. It has a half-life of 5730 years.
All living tissues like plants and animal absorbed carbon-12 along with carbon-14 with same ratio of caebon-14 to carbon-12 in the atmosphere.
Carbon-14 dating is based on the ratio of carbon-14 to carbon-12 in the atmosphere which is relatively constant
the answer is a chemical element
