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rusak2 [61]
3 years ago
10

Alguien sabe el nombre del compuesto etilisopropilacetileno?​

Chemistry
1 answer:
Paladinen [302]3 years ago
3 0
Noooooooooooooooooooooo
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What is the frequency of light that has an energy of 3.98 x 10-18 J
Dominik [7]
This is what i have found i hope this helps

8 0
2 years ago
0.2640 g of sodium oxalate is dissolved in a flask and requires 30.74 mL of potassium
Free_Kalibri [48]

Moles of potassium permanganate = 0.0008

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Reaction

5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) +  10CO2(g) + 8H2O(1)

The end point ⇒titrant and analyte moles equal

titrant : potassium  permanganate-KMnO4

analyte : sodium oxalate - Na2C2O4

so moles of KMnO4 = moles of Na2C2O4

moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{0.264}{134 g/mol}\\\\mol=0.002

From equation, mol ratio  Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :

\tt \dfrac{2}{5}\times 0.002=0.0008

6 0
3 years ago
In the balanced reaction below, what is the mole ratio comparing iron (Fe) and oxygen gas (O2)?
zepelin [54]

The given balanced reaction is,

4Fe(s) + 3O_{2}(g) --->2Fe_{2}O_{3} (s)

The stoichiometric coefficients of each element or compound represents the number of moles of that element or compound required for the complete reaction to take place.

The mole ratios of different products and reactants will be:

\frac{Fe}{O_{2}} = \frac{4 mol Fe}{3 mol O_{2}}

\frac{Fe}{Fe_{2}O_{3}} = \frac{4 mol Fe}{2 Fe_{2}O_{3}}

\frac{O_{2}}{Fe_{2}O_{3}} =\frac{3 mol O_{2}}{2molFe_{2}O_{3}}

So the mole ratio comparing iron (Fe) and oxygen gas (O_{2}) is

4 : 3

5 0
3 years ago
Read 2 more answers
A sample of an unknown compound with a mass of 0.847 g has the following composition: 50.51 % fluorine and 49.49 % iron. When th
sergejj [24]

Answer: 0,4278g of F and 0,4191g of Fe

Explanation: it's possible to calculate the mass of each element by multiplying the percentage (decimal) of the element by the mass of the compound.

For Fluorine (F)

0,847g * 0,5051 = 0,4278g of F

For iron (Fe)

0,847 * 0,4949 = 0,4191g of Fe

This is determined because even when the compound is decomposed, due to conservative law of mass, the decomposition process do not affect the amount of matter, so the mass of the elements remain even if they are separated from the original molecule.

At the end, the sum of the elements masses should be the total mass of the compound.

4 0
3 years ago
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if you are asked to help the laboratory assistant in separating the mixture which method will you see?​
FromTheMoon [43]

Answer:

use secondary data. the normal method to use

3 0
3 years ago
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