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yawa3891 [41]
3 years ago
15

If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro

benzene = 123.06 g/mole) report answers to one decimal place
Chemistry
1 answer:
In-s [12.5K]3 years ago
7 0

Molality is defined as 1 mole of a solute in 1 kg of solvent.  

Molality=

\frac{Number of moles of solute}{Mass of solvent in kg}

Number of moles of solute, n=  

\frac{Given mass of the substance}{Molar mass of the substance}

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,  

n= \frac{0.2 }{123.06}

Number of moles of nitrobenzene, n= 0.0016  mol

Mass of 10.9 g of naphthalene in kg=0.0109  

Molality= \frac{0.0016}{0.0109 }

Molality= 0.146 m

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Answer:

31.58 L

Explanation:

From the question given above, the following data were obtained:

Initial mole (n₁) of gas = 1.90 moles

Initial volume (V₁) = 40 L

Final mole (n₂) = 1.90 – 0.40 = 1.5 moles

Final volume (V₂) =.?

The final volume of the gas can be obtained as follow;

V₁ / n₁ = V₂ / n₂

40 / 1.9 = V₂ / 1.5

Cross multiply

1.9 × V₂ = 40 × 1.5

1.9 × V₂ = 60

Divide both side by 1.9

V₂ = 60 / 1.9

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2 years ago
How many calories is 130. joules?
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3 years ago
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aliina [53]
<h3>Answer:</h3>

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What volume of carbon dioxide (CO2) will be produced if 2.90 moles of it on (Fe) is produced?
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Answer:

= 97.44 Liters at S.T.P

Explanation:

The reaction between Iron (iii) oxide and Carbon monoxide is given by the equation;

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