298 g of calcium carbonate CaCO₃
Explanation:
We have the following chemical reaction:
CaCN₂ (s) + 3 H₂O (l) → CaCO₃ (s)+ 2 NH₃ (g)
number of moles = mass / molar weight
number of moles of H₂O = 161 / 18 = 8.94 moles
Knowing the chemical reaction we devise the following reasoning:
if 3 moles of H₂O produces 1 mole of CaCO₃
then 8.94 moles of H₂O produces X moles of CaCO₃
X = (8.94 × 1) / 3 = 2.98 moles of CaCO₃
mass = number of moles × molar weight
mass of CaCO₃ = 2.98 × 100 = 298 g
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Answer:
What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid? The amount of acid that was added.
Explanation:
Answer:
Correct option -D
Explanation:
Here, A kinetics experiment is set up is set up to collect the gas that is generated from the cacarbonate and methanoic acid.
Among the given conditions, decreasing the particle size of calcium carbonate only increases the production of gas.
Smaller particles of reactant increases the surface area then followed by rate of reaction will be increases it leads to increases the production of gas.
Therefore, the suitable experimental condition most likely to increase the gas production is-
Decreasing the particle size of the
by grinding it into a fine powder.
Hence, correct option -D.
Answer:
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