All categories

2 years ago

An object with a mass of 5.0 kg accelerates 3.0 m/s2 after a force is applied to it. What is the amount

Physics

1 answer:

Studentka2010 [4]2 years ago

8 0

Answer:

Dont

Explanation:

Know

You might be interested in

PLSS HELP WILL GIVE POINTS OR WHATEVER JUST PLS HELP I WILL GIVE 98 POINTS

galina1969 [7]

Answer:

i am pretty sure you are correct and so sorry if i am wrong i am just trying to help no need to give me anything if i am right but it might be the one abouve the one you chose :) please let me know if i am wrong or right

Explanation:

3 0

3 years ago

The crest of one wave with an amplitude of 4 m meets up with the crest of a second

trapecia [35]

Answer:

Constructive

Explanation:

3 0

3 years ago

The net horizontal force on a car is 981 N. The car has a mass of 1550 kg and the force is applied when the car has a speed of 2

viktelen [127]

Answer:

Distance, d = 778.05 m

Explanation:

Given that,

Force acting on the car, F = 981 N

Mass of the car, m = 1550 kg

Initial speed of the car, v = 25 mi/h = 11.17 m/s

We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:

$F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{981}{1550}\\\\a=0.632\ m/s^2$

Let d is the distance covered by car. Using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2\\\\d=11.17\times 35+\dfrac{1}{2}\times 0.632\times (35)^2\\\\d=778.05\ m$

So, the car will cover a distance of 778.05 meters.

5 0

4 years ago

A car battery has a rating of 250 ampere-hours. This rating is one indication of the total charge that the battery can provide t

Serga [27]

Answer:

Total charge provided by the battery could be 900000 C.

Maximum current provided by the battery for 37 minutes could be 405.405 A

Explanation:

Rating= 250 A-h

a. Total charge:

$Rating=Q/t\\Q=Rating.t\\$

Suppose t=1h

$Q=250 A(1h)\\Q=250 A(3600 sec)\\Q= 900000 A.sec$

We konw that $Ampere=\frac{Coulomb}{sec}$ , replacing:

$Q=900000(\frac{Coulomb}{sec})(sec)\\Q=900000 Coulomb$

Total charge provided by the battery could be 900000 C.

b. Maximum current for 37 minutes

$I=\frac{Q}{t} \\I=\frac{900000 C}{37*60 sec}\\I=405.405 A$

Maximum current provided by the battery for 37 minutes could be 405.405 A

4 0

3 years ago

2 kilogram bowling ball sits on top of a building that is 40 m the object has k e or g p e or both be sure to include the correc

Licemer1 [7]

GPE=mass*GFS*height
2kg*9.8N/Kg*40m -I've used the Grabitational field strength of the earth's
surface

=784J

7 0

3 years ago