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GenaCL600 [577]
3 years ago
15

D. Fill in the blanks in the following paragraph to correctly identify the conductive properties of materials. (1 point)

Physics
1 answer:
Salsk061 [2.6K]3 years ago
4 0

Answer:

conductor, insulator, resists, semiconductor, 3 and 5 group

Explanation:

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When the motion of one or both of the particles is at an angle to the line of impact, the impact is said to be ________
Nana76 [90]

Answer: Oblique impact

Explanation:

When the motion of one or both of the particles is at an angle to the line of impact, the impact is said to be oblique impact.

On the other hand, when the directions of motion of the two colliding particles are moving along a line of impact, then it's refered to as central impact.

7 0
3 years ago
What is the kinetic energy of a hammer that starts from rest and decreases its potential energy by 10 kJ?
erma4kov [3.2K]

Answer:

final kinetic energy of the hammer is 10 kJ

Explanation:

As we know that there is no non conservative force on the system

So here we can use the theory of mechanical energy conservation

So we will have

\Delta K + \Delta U = 0

here we know that

\Delta U = - 10 kJ

from above expression now

K_f - K_i - 10 kJ = 0

K_f - 0 = 10 kJ

so final kinetic energy of the hammer is 10 kJ

3 0
3 years ago
The metal ions in iron are held together by
Sidana [21]
Metals are giant structures of atoms held together by metallic bonds. “Giant” implies that large but variable numbers of Atoms are involved - depending on the size of the bits of metal. most metals are close packed - that is, they fit as many items as possible into the available volume.
5 0
3 years ago
A 2.0-kg object moving with a velocity of 5.0 m/s in the positive x direction strikes and sticks to a 3.0-kg object moving with
Andrej [43]

Answer:

5.4 J.

Explanation:

Given,

mass of the object, m = 2 Kg

initial speed, u = 5 m/s

mass of another object,m' = 3 kg

initial speed of another orbit,u' = 2 m/s

KE lost after collusion = ?

Final velocity of the system

Using conservation of momentum

m u + m'u' = (m + m') V

2 x 5 + 3 x 2 = ( 2 + 3 )V

16 = 5 V

V = 3.2 m/s

Initial KE = \dfrac{1}{2}mu^2 + \dfrac{1}{2}m'u'^2

              = \dfrac{1}{2}\times 2\times 5^2 + \dfrac{1}{2}\times 3 \times 2^2

              = 31 J

Final KE = \dfrac{1}{2} (m+m')V^2 = \dfrac{1}{2}\times 5 \times 3.2^2 = 25.6 J

Loss in KE = 31 J - 25.6 J = 5.4 J.

4 0
3 years ago
Consider a 2250-lb automobile clocked by law-enforcement radar at a speed of 85.5 mph (miles/hour). if the position of the car i
Korvikt [17]

As per law of Heisenberg uncertainty law

product of uncertainty in position and uncertainty in momentum will be constant

\Delta x . \Delta P = \frac{h}{4\pi}

\Delta x . m \Delta v = \frac{h}{4\pi}

now plug in all data

(5\times 0.3048). (2250 \times 0.454) \Delta v = \frac{6.6 \times 10^{-34}}{4\pi}

\Delta v = 3.37 \times 10^{-38} m/s

So above is the uncertainty in velocity of the object

4 0
3 years ago
Read 2 more answers
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