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Artemon [7]
2 years ago
8

2) A swinging motion of a Pendulum of clock is _______

Physics
1 answer:
VashaNatasha [74]2 years ago
3 0

Oscillatory motion.(also known as Periodic motion)

Hope it helps...

Regards,

Leukonov/Olegion.

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In which electric circuit would the voltmeter read 10 volts ?
ki77a [65]

Given that,

Voltage = 10 volt

Suppose, The three resistance is connected in parallel and each resistance is 12 Ω. find the current in the electric circuit.

We need to calculate the equivalent resistance

Using formula of parallel

\dfrac{1}{R}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}

Put the value into the formula

\dfrac{1}{R}=\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}

\dfrac{1}{R}=\dfrac{1}{4}

R=4\ \Omega

We need to calculate the current in the circuit

Using ohm's law

V=IR

I=\dfrac{V}{R}

Where, V = voltage

R = resistance

Put the value into the formula

I=\dfrac{10}{4}

I=2.5\ A

Hence, The current in the circuit is 2.5 A

4 0
2 years ago
Football helmets are made with padding that helps reduce head injuries when a player collides with an object. Which bestexplains
Vlad1618 [11]

football hemets have pads that are filled with air and thick foam so when they are hit the foam asorbs the hit and the air keeps the hard outer shell of the helmet from hiting the players head

3 0
3 years ago
Read 2 more answers
Please help im being timed on this and need to get my grade up
nadya68 [22]

Answer:

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8 0
2 years ago
You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N while the opposing force of
Rzqust [24]

Answer:

<h2>3.36J</h2>

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

                                       = 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

<u>Therefore the work of the 1.55N 3.36J</u>

4 0
2 years ago
A. State whether the acceleration is positive, negative or zero for each section in the speed versus
bazaltina [42]

Answer:

a=positive

b=0

c=positive

d=negative

Explanation:

a=acceleration depends on the speed and time. if the speed and time are increasing at the same rate, the acceleration value will be positive as the vehicle is speeding up.

b=the speed and time are not increasing, therefore the vehicle is either stationary or travelling at a steady pace.

c=same explanation as a

d=the speed and time are not increasing at the same rate as the speed is decreasing. this means that the car is slowing down

5 0
2 years ago
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