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2 years ago

15

PLEASE SOMEBODY HELP! I’ve been stuck on this question for nearly 5 hours because I literally have no idea what to do somebody p

lease help

1 answer:

shusha [124]2 years ago

7 0

Answer:

Well We need to get rid of 1200 mb so your estimated guess would be to delete~2523~ photos If i get this wrong Im very sorry.

Step-by-step explanation:

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Why did the donkey get q passport

Sauron [17]

Answer:

because it can go overseas

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3 years ago

Question 3 ! Please! I need help

Ymorist [56]

To construct a perpendicular bisector you set the compass to a span which is greater than half the length of the given line. Then setting the point at one end of the line construct an arc passing through the line . Then repeat this process from the other side of the line keeping the compass at the same setting.

Now draw the perpendicular bisector through the 2 intersections of the arcs. That's it.

3 0

2 years ago

Find the perimeter of a quadrilateral with vertices at C (-1, 2), D (-2, -1), E (2, -2), and F (1, 1). Round your answer to the

babymother [125]

Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

$d=\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2} }$

DC:

D(-2,-1) C(-1,2)

$d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2} } \\d=\sqrt{10} =3.16$

CF:

C(-1,2) F(1,1)

$d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2} } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24$

FE

F(1,1) E(2,-2)

$d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16$

ED

E(2,-2) D(-2,-1)

$d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2} } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\$

3.16+2.24+3.16+4.12= 12.68

4 0

2 years ago

Please help ill give brainliest

Nata [24]

I am pretty sure the answer is c

6 0

3 years ago

Read 2 more answers

Which relation is a function ?

Leokris [45]

Answer:

Bottom left

Step-by-step explanation:

If you can draw a vertical line through a graph and touch only one point, the relation is a function.

3 0

3 years ago