Question

In the reaction h2so4 + na2co3 → na2so4 + co2 + h2o 14.5 g of water is collected. what is the molarity of sulfuric acid if 1.78 l were used in the reaction? 1. 146 m 2. 0.453 m 3. 1.43 m 4. 0.697 m 5. 1.78 m6. 0.0046 m

Answer 1

H2SO4 + Na2CO3  → Na2SO4 + CO2 + H2O

The molarity  of  sulfuric acid  if  1.78  L  were used  in the   above reaction is
 0.453 M  (answer 2)

      Calculation
find the  moles of water  produced  = mass/molar  mass

=   14.5 g /18 g/mol  = 0.806  moles

by use of of mole ratio  between  H2So4  to H2O   which is 1:1  the    moles    of   H2SO4   is also =  0.806   moles


Molarity  of H2SO4 is therefore =    moles/volume  in   liters

=  0.806   mol/  1.78 L  =  0.453 M (answer 2)