How many cm3 are there in 1 dm3?

A kite is hovering over the ground at the end of a straight 38-m line. the tension in the line has a magnitude of 17 n. wind blo

postnew [5]

Let the tension in the thread will be at angle theta

now by force balance in x and y directions we can say

$17 cos\theta = 18 cos60$

$17 cos\theta = 9$

$\theta = 58.03 degree$

now for the height of the kite we can use

$h = L sin\theta$

$h = 38 sin58.03$

$h = 32.23 m$

<em>so it will be at height 32.23 m from ground</em>

3 0

3 years ago

Oceanographers use submerged sonar systems, towed by a cable from a ship, to map the ocean floor. In addition to their downward

KATRIN_1 [288]

Answer:

Tension in the cable is T = 16653.32 N

Explanation:

Give data:

Cross section Area A = 1.3 m^2

Drag coefficient CD = 1.2

Velocity V = 4.3 m/s

Angle made by cable with horizontal =30 degree

Density $\rho \ of\ water= 1000 kg/m3$

Drag force FD is given as

$F_{D} = \fracP{1}{2} \rho v^{2} C_{D} A$

$= 0.5\times 1000\times 4.32\times 1.2\times 1.3$

Drag force = 14422.2 N acting opposite to the motion

As cable made angle of 30 degree with horizontal thus horizontal component is take into action to calculate drag force

TCos30 = F_D

$T = \frac{F_D}{cos30}$

$T =\frac{ 14422.2}{cos 30}$

T = 16653.32 N

7 0

3 years ago

Suppose a scientist doing an experiment in nuclear fusion starts out with twelve atoms. How many atoms will most likely result f

ddd [48]

<span>So we wan't to know what happens during nuclear fusion where we have 12 atoms. Nuclear fusion is a nuclear process where 2 or more nuclei will form 1 or more different nuclei with a release of energy. So if we start with 12 atoms, the most likely result will be 6 atoms. </span>

3 0

3 years ago

Read 2 more answers

Example 7.3

marysya [2.9K]

Answer:

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4 0

3 years ago

"Two uniform identical solid spherical balls each of mass M and radius R" and moment of inertia about its center 2/5 MR2 are rel

adelina 88 [10]

Answer:

he sphere that uses less time is sphere A

Explanation:

Let's start with ball A, for this let's use the kinematics relations

v² = v₀² - 2g (y-y₀)

indicate that the sphere is released therefore its initial velocity is zero and when it reaches the floor its height is zero y = 0

v² = 0 - 2 g (0- y₀)

v = $\sqrt{2g y_o}$

v = $\sqrt{2 \ 9.8\ H}$

v = 4.427 √H

Now let's work the sphere B, in this case it rolls down a ramp, let's use the conservation of energy

starting point. At the highest point, before you start to move

Em₀ = U = m g y

final point. At the bottom of the ramp

Em_f = K = ½ m v² + ½ I w²

notice that we include the kinetic energy of translation and rotation

energy is conserved

Em₀ = Em_f

mg H = ½ m v² + ½ I w²

angular and linear velocity are related

v = w r

w = v / r

the momentorot of inertia indicates that it is worth

I = $\frac{2}{5}$ m r²

we substitute

m g H = ½ m v² + ½ ( $\frac{2}{5}$ m r²) ( $\frac{v}{r}$ )²

gH = $\frac{1}{2}$ v² + $\frac{1}{5}$ v² = $\frac{7}{10}$ v²

v = $\sqrt{\frac{10}{7} \ g H}$

v = $\sqrt{ \frac{10}{7} \ 9.8 \ H}$

v=3.742 √H

Taking the final speeds of the sphere, let's analyze the distance traveled, sphere A falls into the air, so the distance traveled is H. The ball B rolls in a plane, so the distance (L) traveled can be found with trigonometry

sin θ = H / L

L = H /sin θ

we can see that L> H

In summary, ball A arrives with more speed and travels a shorter distance, therefore it must use a shorter time

Consequently the sphere that uses less time is sphere A

5 0

3 years ago