To solve this problem it is necessary to use the concepts related to pressure depending on the depth (or height) in which the object is on that fluid. By definition this expression is given as
Where,
Atmospheric Pressure
Density, water at this case
g = Gravity
h = Height
The equation basically tells us that under a reference pressure, which is terrestrial, as one of the three variables (gravity, density or height) increases the pressure exerted on the body. In this case density and gravity are constant variables. The only variable that changes in the frame of reference is the height.
Our values are given as
Replacing at the equation we have,
Therefore the pressure inside the hose is 0.1089Mpa
Answer:
F = 1.07 x 10⁻⁷ N
Explanation:
The gravitational force of attraction between two objects can be found by the use of Newton's Gravitational Law:
where,
F = Gravitational Force of attraction = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = m₂ = mass of spheres = 20 kg
r = distance between the objects = 50 cm = 0.5 m
Therefore,
<u>F = 1.07 x 10⁻⁷ N</u>
Answer:
The electric field outside the sphere will be .
Explanation:
Given that,
Radius of solid sphere = R
Charge = q
According to figure,
Suppose r is the distance between the point P and center of sphere.
If be the volume charge density,
Then, the charge will be,
.....(I)
Consider a Gaussian surface of radius r.
We need to calculate the electric field outside the sphere
Using formula of electric field
Put the value from equation (I)
Hence, The electric field outside the sphere will be .
Answer:
3.75 m/s^2
Explanation:
The centripetal acceleration of an object in uniform circular motion is given by the equation:
where
v is the tangential speed of the object
r is the radius of the trajectory
In this problem, r = 60 m and v = 15 m/s, therefore the centripetal acceleration of the car is
Answer:
b > 66.41 kg/s
Explanation:
The spring force F = -kx, where k = spring constant, the damping force f = -bv. The net force F' = F + f
F + f = ma
-kx - bv = ma
-kx -bdx/dt = md²x/dt².
Re-arranging the equation, we have
So, md²x/dt² + bdx/dt + kx = 0
Dividing through by m, we have
d²x/dt² + (b/m)dx/dt + (k/m)x = 0
This is a second-order differential equation. The characteristic equation is thus,
D² + (b/m)D + (k/m) = 0
Using the quadratic formula, we find D.
For an overdamped system,
Now, k = F/x. Since the weight of the object causes the spring to stretch a distance of 0.5 m, k = mg/x where m = mass of object = 0.75 kg, g = 9.8 m/s² and x = x₀ =0.5 m.
Substituting k = mg/x into the inequality for b, we have
b > 2√{(mg/x₀)m}
b > 2√{(m²g/x₀)}
b > 2m√{g/x₀)}
b > 2 × 0.75 kg√{9.8 m/s²/0.5 m)}
b > 1.5 kg√{19.6/s²)}
b > 1.5 kg × 4.427/s
b > 66.41 kg/s
Answer:
Explanation:
mass of proton, m = 1.67 x 10^-27 kg
speed of proton, v = 350 km/s = 350,000 m/s
Momentum of proton, p = mass x speed
p = 1.67 x 10^-27 x 350000 = 5.845 x 10^-22 kg m /s
uncertainty in momentum, Δp = 0.1 % of p
Δp =
According to the principle
where, Δx be the uncertainty in position