Atomic mass Si = 28.0855 u.m.a
28.0855 g -------------------- 6.02x10²³ atoms
3.96x10³ g ------------------- ?? atoms
( 3.96x10³) x 6.02x10²³ / 28.0855 =
8.48x10²⁵ atoms
Answer: The name of the
is Iodine tetrabromide and it is a covalent compound.
Explanation:
Inter-halogen compounds are compounds which composed of two different halogen atoms. For example ;
etc.
The naming is done by first writing the central atom symbol's name followed by the prefix corresponding to the number of atoms of another halogen atom like: Mono for 1, di ,for 2 tri for 3, tetra for 4 , penta for 5 etc. After this name of the another halogen is written with suffix 'ide' in the end.
The name of the
is Iodine tetra bromide.
In halogen compounds, the difference in electronegativities is not so large due to which they form covalent compounds by the means of sharing the electrons. Hence the Iodine tetrabromide covalent compound.
An object becomes negatively charged when it gains electrons, because electrons have a negative charge.
Answer:
(a) Homogeneous. 4.7 g of MgCl₂.
(b) 9.1 g
Explanation:
(a)
At 200°C, we can dissolve 54.6g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:

Since we can dissolve up to 20.9 g of MgCl₂ and we added only 16.2 g, the mixture is homogeneous and we could add 20.9 g -16.2 g = 4.7 g of solute to make it saturated.
(b)
At 800°C, we can dissolve 66.1 g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:

Since we can dissolve up to 25.3 g of MgCl₂ and we added only 16.2 g, we could add 25.3 g - 16.2 g = 9.1 g of solute to make it saturated.
Answer:
0.2193 μm
Explanation:
The reaction showing the Photodissociation of ozone (O3) is given below as:
O₃ + hv --------------------------> O₂ + O⁺
H° (142.9) (0) (438kJ/mol).
The first thing to do here is to determine the change in the enthalpy of the total reaction, this can be done by subtracting the change in the enthalpy of the reactant from the change in enthalpy in the product. Hence, we have:
ΔH° = [438 kJ/mol + 247.5 kJ/mol] - (142.9) = 542.6 KJ/mol.
This value, that is 542.6 KJ/mol will then be used in the determination of the value for the maximum wavelength that could cause this photodissociation.
Therefore, the maximum wavelength could cause this photodissociation ≤ h × c/ E = [ 1.199 × 10⁻⁴]/ 542.6 = 2.193 × 10⁻⁷ = 0.2193 μm