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dusya [7]
3 years ago
11

Na2CO3(aq)+2HCl(aq)→2NaCl(aq)+H2O(l)+CO2(g) A student combined two colorless aqueous solutions. One of the solutions contained N

a2CO3 as the solute and the other contained HCl . The chemical reaction that took place is represented by the equation above. What experimental result would be evidence that a chemical reaction took place when the solutions were combined?
Chemistry
1 answer:
Scrat [10]3 years ago
7 0

Answer: Bubbles formed would be evidence that a chemical reaction took place when the solutions were combined.

Explanation:

As it is given that both Na_{2}CO_{3} and HCl chemically combine together leading to the formation of NaCl, water and carbon dioxide gas. As the gas is forming and its formation will also form bubbles into the solution.

This formation of bubbles actually indicate that a chemical reaction has taken place. As molecules of a gas are held by Vander waal forces so, this gas will readily escape into the atmosphere.

Thus, we can conclude that bubbles formed would be evidence that a chemical reaction took place when the solutions were combined.

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Please calculate the mixed volume (Vmix) when 0.300 mol of ethanol and 0.200 mol of water are mixed. Hint: The partial molar vol
Grace [21]

Answer:

If we assume the molar volumes of water and ethanol 17.0 and 57.0 cm³/mol, respectively, Vmix = 20.5 cm³.

Explanation:

The molar volume of a substance is the ratio between the volume and the number of moles of the substance. It represents the volume that 1 mol of it occupies. Because we don't have access to page 24, let's assume the molar volumes of water and ethanol 17.0 and 57.0 cm³/mol, respectively.

The volume of mixture (Vmix) is the sum of the volume of each substance, which is the number of moles multiplied by molar volume, so:

Vmix = 0.300*57 + 0.200*17

Vmix = 17.1 + 3.4

Vmix = 20.5 cm³

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3 years ago
Which of the following phrases best describes a synthesis reaction?
iogann1982 [59]
Answer is D breaking apart I to not more than two
4 0
3 years ago
Suppose that 25.0 mL of 0.440 M sodium chloride is added to 25.0 mL of 0.320 M silver nitrate. How many moles of silver chloride
d1i1m1o1n [39]

The number of moles of silver chloride that will precipitate is 0.008 mole

From the question,

We are to determine the number of moles of silver chloride that will precipitate

First,

We will write a balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

NaCl + AgNO₃ → AgCl + NaNO₃

This means

1 mole of sodium chloride reacts with 1 mole of silver nitrate to produce 1 mole of silver chloride and 1 mole of sodium nitrate

Now, we will determine the number of moles of each reactant present

  • For sodium chloride (NaCl)

Concentration = 0.440 M

Volume = 25.0 mL = 0.025 L

Using the formula

Number of moles = Concentration × Volume

∴ Number of moles of NaCl present = 0.440 × 0.025

Number of moles of NaCl present = 0.011 mole

  • For silver nitrate (NaNO₃)

Concentration = 0.320 M

Volume = 25.0 mL = 0.025 L

∴ Number of moles of NaNO₃ present = 0.320 × 0.025

Number of moles of NaNO₃ present = 0.008 mole

From the balanced chemical equation,

1 mole of sodium chloride reacts with 1 mole of silver nitrate to produce 1 mole of silver chloride

Then,

0.008 mole of sodium chloride will react with the 0.008 mole of silver nitrate to produce 0.008 mole of silver chloride

∴ 0.008 mole of silver chloride will be produced

Hence, the number of moles of silver chloride that will precipitate is 0.008 mole

Learn more here: brainly.com/question/18434602

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Mkey [24]
Radium and polonium is the answer to this question. I hope I helped out!
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salantis [7]

Answer:

I think you meant rock defination in science

Explanation:

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or

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