Question

A uniform conducting rod of length 34 cm has a potential difference across its ends equal to 39 mV (millivolts). What is the magnitude of the electric field inside the conductor in units of N/C?

Answer 1

Answer:

Electric field, E = 0.114 N/C

Explanation:

Given that,

Length of the conducting rod, l = 34 cm = 0.34 m

The potential difference across the ends of the rod, $V=39\ mV=39\times 10^{-3}\ V$

Let E is the magnitude of electric field inside the conductor. It can be calculated as :

$E=\dfrac{V}{d}$

$E=\dfrac{39\times 10^{-3}}{0.34}$

E = 0.114 N/C

So, the  magnitude of the electric field inside the conductor is 0.114 N/C. Hence, this is the required solution.

Answer 2

Electric field is the change in voltage per unit distance

E = ΔV / d

E = 39/34
   
  = 1/147 mV/cm

hope this helps