Answer:
B) exothermic.
Explanation:
Hello!
In this case, we need to keep in mind that exothermic reactions release heat, so they increase the temperature as the final energy is less than the initial energy; in contrast, endothermic reactions absorb heat, so they decrease the temperature as the final energy is greater than the initial energy.
In such a way, when a dissolution process shows off a negative enthalpy of dissolution, we infer it is an exothermic process due to the aforementioned; therefore, the answer is:
B) exothermic
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Answer:
-573.67
Explanation:
whenever energy is released in a chemical reaction, we would then expect the delta H of the reaction to be negative because the reaction is an exothermic reaction.
now we have that 2.81 moles of fuel when it combusts would releases 1612kJ of energy
thus, 1 mole will release 1612/2.81 = -573.67kJ of heat
Therefore the delta H of the reaction = -573.67 kJ/mol
It is not directly over a flame because it depends on the substance you might not want to heat it too much.you never know what could happen
1.hydrogen
2.carbon
3.argon
4.titanium
5.cesium
An ester , propyl methanoate ( HCOOC₃H₇) when reacts with sodium hydroxide( NaOH) forms sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH).
The reaction is as follows:
HCOOC₃H₇+NaOH ⇒HCOONa + C₃H₇OH
So when propyl methanoate is hydrolyzed in water and in NaOH then sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH) forms
