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3 years ago

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Sterling silver is a mixture of the metals silver and copper.It is used to make jewellery.sometimes sterling silver causes green

staining on skin.Which metal do you think is responsible for this?Explain why.

1 answer:

slavikrds [6]3 years ago

8 0

The composition of 925 Sterling Silver lends itself to the occasional green discoloration because of the presence of copper

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Granite is an intrusive igneous rock with large crystals because it cools slowly. Where was this rock most likely formed?

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Calculate the solubility of mn(oh)2 in grams per liter when buffered at ph=7.0. assume that buffer capacity is not exhausted

Vanyuwa [196]

When PH + POH = 14
∴ POH = 14 -7 = 7

when POH = -㏒[OH-]

7 = -㏒ [OH-]
∴[OH-] = 10^-7

by using ICE table:

Mn(OH)2(s) ⇄ Mn2+ (aq) + 2OH-(aq)
initial 0 10^-7
change +X +2X
Equ X (10^-7 + 2X)

when Ksp = [Mn2+][OH-]^2

when Ksp of Mn(OH)2 = 4.6 x 10^-14

by substitution:

4.6 x 10^-14 = X*(10^-7+2X)^2 by solving this equation for X

∴ X =2.3 x 10-5 M

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Consider the reaction: P(s) + 5/2 Cl2(g)PCl5(g) Write the equilibrium constant for this reaction in terms of the equilibrium con

Pani-rosa [81]

Answer: The equilibrium constant for the overall reaction is $K_a\times K_b$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

a) $P(s)+\frac{3}{2}Cl_2(g)\rightarrow PCl_3(g)$

$K_a=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}$

b) $PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)$

$K_b=\frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

For overall reaction on adding a and b we get c

c) $P(s)+\frac{5}{2}Cl_2(g)\rightarrow PCl_5(g)$

$K_c=\frac{[PCl_5]}{[Cl_2]^\frac{5}{2}}$

$K_c=K_a\times K_b=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}\times \frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

The equilibrium constant for the overall reaction is $K_a\times K_b$

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