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Sergio039 [100]
3 years ago
8

Pls help All objects above _____ emit radiation. 0°C 0°F 0 K 100 K

Physics
2 answers:
aivan3 [116]3 years ago
8 0
<span>All objects above 0(zero)K emit radiation.</span>
sveta [45]3 years ago
6 0
All objects above absolute 0 (0 k) emit radiation.
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A diver is on a board 1.80 m above
Virty [35]

Answer:

v = 6.95 m/s

Explanation:

Given that,

A diver is on a board 1.80 m above  the water, s = 1.8 m

The initial speed of the diver, u = 3.62 m/s

Let v is the speed with which she hit the water. It will move under the action of gravity. Using the equation of motion as follows :

v^2-u^2=2gs\\\\v=\sqrt{u^2+2gs} \\\\v=\sqrt{(3.62)^2+2(9.8)(1.8)} \\\\v=6.95\ m/s

So, she will hit the water with a speed of 6.95 m/s.

8 0
3 years ago
Read 2 more answers
Lesson 11: electricity &amp; magnetism unit test physical science b unit 5: electricity and magnetism (connexus)
vovikov84 [41]

Electricity and magnetism can be considered as part of the same phenomenon because both are generated by electromagnetic forces.

<h3>What is electricity?</h3>

Electricity is the movement or flow of negatively charged electrons through a suitable conductor where a charge is applied.

Moreover, magnetism is a natural phenomenon caused by the generation/movement of electric charges.

In conclusion, electricity and magnetism can be considered as part of the same phenomenon because both are generated by electromagnetic forces.

Learn more on electricity and magnetism here:

brainly.com/question/25144822

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5 0
2 years ago
The equation below is for potassium oxide.
Reika [66]
The answer is C 4:1.
7 0
3 years ago
Read 2 more answers
A green truck is moving to the right. A red truck is moving to the left with a speed of 6 m/s. The mass of the red truck is 1,00
Contact [7]

Answer:

2 m/s

Explanation:

m_1 = Mass of red truck = 1000 kg

m_2 = Mass of green truck= 3000 kg

u_1 = Initial Velocity of red truck = 6 m/s

u_2 = Initial Velocity of green truck

v = Velocity with which they move together = 0

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow m_1u_1 + m_2u_2 =0\\\Rightarrow m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow m_1u_1 + m_2u_2 =0\\\Rightarrow u_2=-\frac{m_1u_1}{m_2}\\\Rightarrow u_2=-\frac{1000\times 6}{3000}\\\Rightarrow u_2=-2\ m/s

Velocity of the green truck is 2 m/s

8 0
3 years ago
A potential difference of 1.20 V will be applied to a 33.0 m length of 18-gauge copper wire (diameter = 0.0400 in.). Calculate (
Nostrana [21]

Answer:A) Current = 1.739A, B)current density, J = 2.147x10^6 A/m2

magnitude of electric field , E =  0.036 N/C

)rate of thermal energy, P  =2.086W

Explanation:

Resistance  = R =   ρL/A

But the cross-section area of the wire. is given as

Diameter / 2 = 0.04/2 =0.02in to m = 0.02 / 39.37= 0.000508

A = πr^2 = π x  0.000508^2 = 8.10 x 10^-7

since resistivity of copper,ρ= 17x10-9 ohm.m

so resistance is   R =   ρL/A

17x10-9  x 33 / 8.1x10-7

= 0.69 ohm.

A) Current =    I = Voltage /Resistance =1.20/0.69 =1.739A

B)current density, J = Current /Area

= 1.739/8.1x10-7

= 2.147x10^6 A/m2

c)magnitude of electric field , E =  Current density x resistivity =J ρ

E = 2.147 x 10^6  x 17  x 10^-9

E = 0.036 N/C

D)rate of thermal energy, P  = I² R =1.739² X 0.69

=2.086W

6 0
3 years ago
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