Answer:

Explanation:
4HCl + O₂ ⇌ 2Cl₂ + 2H₂O
E/mol·L⁻¹: 0.80 0.20 3.0 3.0
![K_{\text{eq}} = \dfrac{\text{[Cl$_{2}$]$^{2}$[H$_{2}$O]$^{2}$}}{\text{[HCl]$^{4}$[O$_{2}$]}} = \dfrac{3.0^{2}\times3.0^{2}}{0.80^{4}\times 0.20} = \mathbf{990}\\\\\text{The $K_{\text{eq}}$ value is $\large \boxed{\mathbf{990}}$}](https://tex.z-dn.net/?f=K_%7B%5Ctext%7Beq%7D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BCl%24_%7B2%7D%24%5D%24%5E%7B2%7D%24%5BH%24_%7B2%7D%24O%5D%24%5E%7B2%7D%24%7D%7D%7B%5Ctext%7B%5BHCl%5D%24%5E%7B4%7D%24%5BO%24_%7B2%7D%24%5D%7D%7D%20%3D%20%5Cdfrac%7B3.0%5E%7B2%7D%5Ctimes3.0%5E%7B2%7D%7D%7B0.80%5E%7B4%7D%5Ctimes%200.20%7D%20%3D%20%5Cmathbf%7B990%7D%5C%5C%5C%5C%5Ctext%7BThe%20%24K_%7B%5Ctext%7Beq%7D%7D%24%20value%20is%20%24%5Clarge%20%5Cboxed%7B%5Cmathbf%7B990%7D%7D%24%7D)
I am assuming that the compounds given are Pentane, 3-methyl-hexane, and 2, 4-dimethylpentane considering that the compounds were not separated by a comma.
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Pentane is in the form of a straight chain alkane. This is important as there are many isomers of Pentane, taking different shapes. By it's name it consists of 5 carbon atoms, and the number of hydrogen atoms should be 12, as the compound is nonpolar.
3-methylhexane is an alkane present in a hexane structure at position 3. There are thus 3 molecules at 3 ends of a hexane structure - H3C, CH3, and CH3
2,4-dimethylpentane is an alkane with respect to the formula [(H3C)2CH]2CH2.
With that information, refer to the three attachments below, for each compound given. They are in order -
There's two sig figs: the 1 and the zero. The 10^-2 contributes no sig figs.
Answer:
C
Explanation:
If the enthalpy change (i.e. Δ<em>H</em>) of a reaction is negative, then the reaction releases heat and is hence exothermic.
Hence, our answer is C.
Conversely, if Δ<em>H</em> is positive, the reaction absorbs heat and is endothermic.
Δ<em>H</em> tells us nothing about the speed of the reaction.
While Δ<em>H</em> influences free-energy change (Δ<em>G</em> = Δ<em>H</em> - <em>T</em>Δ<em>S</em>), we cannot predict the sign of Δ<em>G</em> given only Δ<em>H </em>(recall that a reaction is spontaneous if Δ<em>G</em> < 0).
Explanation:
General electronic configuration for the given groups are as follows.
For 4A(14) : 
This means that there are 4 unpaired electrons in group 4A(14).
For 7A(17) :
So, there are 7 unpaired electrons present in group 7A(17).
For 1A(1) : 
Hence, there is only one unpaired electron present in group 1A(1).
For 6A(16) :
So, there are 6 unpaired electrons present in group 6A(16).