Question

Calculate the mass of xenon difluoride gas with a volume of 0.223 L, pressure of 0.799 atm and temperature of 47.0 oC.

Answer 1

The mass of the gases can be determined by the moles of the gas in the ideal equation. The mass of xenon difluoride at 0.799 atm is 0.011 gms.

What is an ideal gas equation?

An ideal gas equation gives the moles of the substance from the temperature, volume, and pressure of the gas. The ideal gas equation can be shown as:

n = PV ÷ RT

Here, n = mass ÷ molar mass

Given,

Volume of xenon difluoride (V) = 0.223 L

Pressure of xenon difluoride (P) = 0.799 atm

Temperature of xenon difluoride (T) = 320.15 Kelvin

Gas constant (R) = 8.314 J⋅K⁻¹⋅mol⁻¹

The moles of the gas is calculated as:

n = PV ÷ RT

= 0.223 × 0.799 ÷ 8.314 × 320.15

= 0.1781 ÷ 2661.72

= 6.69 × 10⁻⁵ moles

Mass is calculated as:

169.29 × 6.69 × 10⁻⁵ = 0.011 gm

Therefore, 0.011 gms is the mass of xenon difluoride.

Learn more about ideal gas here:

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