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When 100.g Mg3N2 reacts with 75.0 g H2O, what is the maximum theoretical yield of NH3?

Temka [501]

Answer : The correct option is, 23.6 g

Explanation : Given,

Mass of $Mg_3N_2$ = 100.0 g

Mass of $H_2O$ = 75.0 g

Molar mass of $Mg_3N_2$ = 101 g/mol

Molar mass of $H_2O$ = 18 g/mol

First we have to calculate the moles of $Mg_3N_2$ and $H_2O$ .

$\text{Moles of }Mg_3N_2=\frac{\text{Given mass }Mg_3N_2}{\text{Molar mass }Mg_3N_2}$

$\text{Moles of }Mg_3N_2=\frac{100.0g}{101g/mol}=0.990mol$

and,

$\text{Moles of }H_2O=\frac{\text{Given mass }H_2O}{\text{Molar mass }H_2O}$

$\text{Moles of }H_2O=\frac{75.0g}{18g/mol}=4.17mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$Mg_3N_2(s)+6H_2O(l)\rightarrow 3Mg(OH)_2(aq)+2NH_3(g)$

From the balanced reaction we conclude that

As, 6 moles of $H_2O$ react with 1 mole of $Mg_3N_2$

So, 4.17 moles of $H_2O$ react with $\frac{4.17}{6}=0.695$ moles of $Mg_3N_2$

From this we conclude that, $Mg_3N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2O$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 6 moles of $H_2O$ react to give 2 moles of $NH_3$

So, 4.17 moles of $H_2O$ react to give $\frac{2}{6}\times 4.17=1.39$ mole of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

Molar mass of $NH_3$ = 17 g/mole

$\text{ Mass of }NH_3=(1.39moles)\times (17g/mole)=23.6g$

Therefore, the maximum theoretical yield of $NH_3$ is, 23.6 grams.

4 0

3 years ago

What is the equation for determining gas pressure?

Advocard [28]

Answer:

Explanation:

First, let's review the ideal gas law, PV = nRT. In this equation, 'P' is the pressure in atmospheres, 'V' is the volume in liters, 'n' is the number of particles in moles, 'T' is the temperature in Kelvin and 'R' is the ideal gas constant (0.0821 liter atmospheres per moles Kelvin)

8 0

3 years ago

Read 2 more answers

Sea level changes occur at a rate of 10 m per 1,000 years. Regional erosion occurs at a rate of 2 m per 1,000 years. Uplift occu

PtichkaEL [24]

<h3>Answer:</h3>

The rate of sea level change is the fastest

<h3>Explanation:</h3>

To determine the process which is the fastest we need to determine the rate at which each occurs in meters per year.

Rate of sea level changes is 10 m per 1,000 years

Therefore, the rate of sea level change = 10 m ÷ 1000 years

= 0.01 m/yr

Regional erosion occurs at 2 m per 1,000 years

Therefore, Rate in meters per seconds = 2 m ÷ 1,000 years

= 0.002 m/year

Uplift occurs at a rate of 0.1 m per 1,000 years

Thus, rate in meters per seconds = 0.1 m ÷ 1,000 years

= 0.0001 m/yr

Therefore, the rate of sea level change is the fastest at a rate of 0.01 meter/year

4 0

3 years ago

10. Tell me one thing that you learned or was significantly cleared up by doing

Alex73 [517]

What do you mean tell me one thing you learned what did you learn

5 0

3 years ago

Metal M has only one oxidation state and forms a compound with the formula MHCO3. Which formula is correct? A.MNO3 b.MNH4 c.M(NO

never [62]

Answer:

The compound with the correct formula is;

A. MNO₃

Explanation:

The number of oxidation states in the metal, M = One oxidation state

The formula of the compound formed by the metal, M = MHCO₃

We note that the ion HCO₃⁻, known as hydrogen carbonate has an oxidation number of -1

Similarly nitrate, NO₃⁻ has an oxidation number of -1, therefore, the metal M can form similar compound formed with HCO₃⁻ with nitrate, and we have;

The possible compounds formed by the metal 'M' includes MHCO₃ and MNO₃.

5 0

3 years ago