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3 years ago

How are the carbon, nitrogen, and oxygen cycles different?

1 answer:

3 0

The CNO cycle (for carbon–nitrogen–oxygen) is one of the two known sets of fusion reactions by which stars convert hydrogen to helium, the other being the proton–proton chain reaction. Unlike the latter, the CNO cycle is a catalytic cycle.

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True or false: Most of the mass of an atom is found in the electron layers.

Nataly_w [17]

I wanna say false, but I’m sorry if I’m wrong :(

3 0

3 years ago

Tin has many possible isotopes. Three of these isotopes are 116sn, 120sn, and 126sn. What is the mass number of each? How many p

Aneli [31]

Isotopes are defined as atoms of same element with different mass number and same atomic number.

Here, atomic number is equal to number of protons and number of electrons, it is denoted by symbol Z thus,

$Z=n_{e}=n_{p}$

and, mass number is equal to sum of number of protons and neutrons, it is denoted by symbol A thus,

$A=n_{p}+n_{n}$

The three isotopes of tin are given, Sn-116, Sn-120 and Sn-126, mass number for these three isotopes is 116, 120 and 126 respectively. Since, they are isotopes thus, atomic number remains the same that is 50.

Since, $Z=n_{e}=n_{p}$ thus, number of protons and electrons will be 50.

For Sn-116,

$A=n_{p}+n_{n}$

Or,

$116=50+n_{n}$

Or,

$n_{n}=116-50=66$

For Sn-120,

$n_{n}=120-50=70$

For Sn-126,

$n_{n}=126-50=76$

Therefore, mass number, number of protons, electrons and neutrons in all three isotopes are:

Sn-116:

Mass number= 116

Protons=50

neutrons=66

electrons=50

Sn-120:

Protons=50

neutrons=70

electrons=50

Sn-126:

Protons=50

neutrons=76

electrons=50

3 0

3 years ago

To what category of elements does an element belong if it is a poor conductor of electricity? (1 point)

qwelly [4]

Nonmetals is the answer

4 0

3 years ago

Rank and explain how the freezing point of 0.100 m solutions of the following ionic electrolytes compare. List from lowest freez

Elden [556K]

Answer:

The solutions are listed from the lowest freezing point to highest freezing point.

Mg₃(PO₄)₂ - AlBr₃ - BeBr₂ - KBr

Explanation:

Colligative property of freezing point, is the freezing point depression.

Formula is:

ΔT = Kf . m . i

Where ΔT = T° freezing pure solvent - T° freezing solution

Kf is the cryoscopic constant

m is molality and i is the Van't Hoff factor (number of ions, dissolved in solution)

In this case, T° freezing pure solvent is 0° because it's water, so the Kf is 1.86 °C/m, and m is 0.1 molal.

The i modifies the T° freezing solution. The four salts, are ionic compounds, so for each case:

BeBr₂ → Be²⁺ + 2Br⁻ i = 3

AlBr₃ → Al³⁺ + 3Br⁻ i = 4

Mg₃(PO₄)₂ → 3Mg²⁺ + 2PO₄⁻³ i = 5

KBr → K⁺ + Br⁻ i = 2

Solution of Mg₃(PO₄)₂ will have the lowest temperature of freezing and the solution of KBr, the highest (always lower, than 0°).

8 0

3 years ago

What is the IUPAC name?

Anastasy [175]

International Union of Pure and Applied Chemistry

4 0

3 years ago