Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

Mathematics

1 answer:

elena-s [515]1 year ago

4 0

Answer:

Step-by-step explanation:

Jason- Two bags 6 tiles each = 1 bag 12 tiles

2/12 for a 5. 2 for 36.

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The product of (a − b)(a − b) is a2 − b2.<br> A. Sometimes<br> B. Always<br> C. Never

Damm [24]

$(a-b)(a-b)=a^2-2ab+b^2\\\\a^2-2ab+b^2=a^2-b^2\\2b^2=2ab\\b^2=ab\implies a=b \vee b=0$

So, sometimes.

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2 years ago

PLEASE HELP ASAP!! TIME LIMIT

horsena [70]

Answer:

X>50 because 5 people spent less than 10 bucks

Step-by-step explanation:

10x5 = 50, so it cant be above 50$

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Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

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