Question

How many moles of BaCl2 are required to react with one mole of Na3PO4?

Answer 1

The chemical reaction between Barium chloride and Na3PO4 takes place as follows:

$3BaCl_{2} + 2Na_{3} PO_{4} ⇒ Ba_{3} (PO_{4})_{2} + 6NaCl$

2 moles of $Na_{3} PO_{4}$ reacts with 3 moles of $BaCl_{2}$.

Thus, 1.5 moles of $BaCl_{2}$ are required to react with 1 mol of $Na_{3} PO_{4}$ in order for the reaction to be completed.

1.5 moles of BaCl2 are required in order to react completely with 1 mole of Na3PO4.

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