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erica [24]
2 years ago
13

What kind of lines have no solution ot a system of equations

Mathematics
1 answer:
professor190 [17]2 years ago
5 0

Answer:

When 2 lines are parallel they have no points in common so there would be no solution in the system. Even if a third line intersects the two parallel lines, there still would not be a solution to all 3 equations in the system.

Step-by-step explanation: I found this and it can help you!

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5

Step-by-step explanation:

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2x=10

×=5

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Which number is the biggest,
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Answer:

I think is A

Step-by-step explanation:

or the answer is jesus :v

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Genesis 19 number to each of her five questo they can have a chance to win door prices at her party she writes the numbers on st
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What is the y-intercept of the quadratic function

f(x) = (x - 6)(x - 2)?What is the y-intercept of the quadratic function

f(x) = (x - 6)(x - 2)?What is the y-intercept of the quadratic function

f(x) = (x - 6)(x - 2)?What is the y-intercept of the quadratic function

f(x) = (x - 6)(x - 2)?

(0,12)

(0,12)

(0,12)

(0,12)

What is the y-intercept of the quadratic function

f(x) = (x - 6)(x - 2)?

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6 0
3 years ago
Solve for x. MUST SHOW ALL WORK TO RECEIVE FULL CREDIT! (See picture for equation)
ioda
\frac{x}{2.4} = \frac{3}{8}

For proportions and to find x we have to cross multiply
8 × (x) = 3 × 2.4

8x = 7.2
Divide by 8 to isolate x

\frac{8x}{8} =  \frac{7.2}{8}
8 and 8 cancels out

x = 0.9
5 0
3 years ago
Read 2 more answers
NEED HELP WITH THESE QUESTIONS
amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =

Applying double C we have:

\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =

By definition of multiplication of powers of the same base we have to place the same base and add the exponents:\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =

Canceling common terms:

\frac {mn ^ 5} {p ^ 4}

Answer:

Option A

Question 2:

We should simplify the following expression:

\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}

So, we have:

\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =

Simplifying common terms:

\frac {1} {y ^ 2z ^ 2}

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

<em>r ^ 2 + 7r + 10: </em>We look for two numbers that multiplied give 10 and added 7:

(r + 5) (r + 2)

<em>r ^ 2-5r-50:</em> We look for two numbers that multiplied give -50 and added -5:

(r-10) (r + 5)

<em>3r-30 = 3 (r-10)</em>

Rewriting the given expression we have:

\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =

We simplify common terms in the numerator and denominator we have:

(r + 2)

Answer:

Option D

4 0
3 years ago
Read 2 more answers
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