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Blababa [14]
3 years ago
14

Would a precipitate form if a solution contained 8.0 x 10-4 m silver nitrate and 1.8 x 10-4 m potassium chromate? you will have

to find ksp values from your text or from another source.
Chemistry
1 answer:
Alina [70]3 years ago
6 0
Chemical reaction: 2Ag⁺(aq) + CrO₄²⁻(aq) → Ag₂CrO₄<span>(s).
</span>Ksp(Ag₂CrO₄) = 1,1·10⁻<span>¹².
</span>[Ag⁺] = c(AgNO₃) = 8.0·10⁻⁴ M.
[CrO₄²⁻] = c(K₂CrO₄) = 1.8·10⁻⁴ M.
Q(Ag₂CrO₄) = [Ag⁺]²·[CrO₄²⁻]. 
Q = (8.0·10⁻⁴ M)² · 1.8·10⁻⁴ M.
Q = 1.152·10⁻¹⁰.
Q<span> > Ksp, </span><span>a precipitate of silver chromate will form.
</span>Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.

<span> [Ag</span>⁺<span>] is equilibrium concentration of silver cations.
[CrO</span>₄²⁻] is equilibrium concentration of chromate anions.


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