Answer:co2
Explanation:because of the oxygen levels
9 g of hydrogen - 42 g of nitrogen
5 g of hydrogen - x g of nitrogen

The mass of nitrogen in the second sample is 23.33 g.
Answer:
MnO2 M n O 2 is an ionic substance without any oxo-anions, therefore its name has the -ide ending.
Atomic number = 42
Name = Molybdenum
Atomic symbol = Mo
Group number = VI(B)6
Mo = Metal
How to find all valves of Z=42?
Here, we are going to find out the name, symbol and group numbers element with the following Z value and their classification as a metal, metalloid, or nonmetal.
The atomic number of the element is 42
Therefore, the name of the element is Molybdenum
The atomic symbol of the element is Mo
The group number of is VI(B)6
Mo is a metal
Hence, the element is Molybdenum
Learn more about atomic symbol here :
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Answer:

Explanation:
Given
The data in the table
Required
Follow the steps appended to the question;
Step 1: Calculate the Mean or Average
Mean = Summation of lengths divided by number of teams;



Step 2: Get The Range



Step 3: Divide Range by 2



Step 4: Determine the Precision

Substitute 2.70 for Average and 0.1 for Approximate Range
