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melamori03 [73]
1 year ago
8

Net ionic equation for Calcium hydroxide reacting with ammonium Chloride?

Chemistry
2 answers:
Anton [14]1 year ago
8 0

Explanation:

ca (OH)2 + 2NH4CL------> CACL2 + 2NH3 + 2H2O

VMariaS [17]1 year ago
3 0

Answer:

Ca(OH)₂ (aq) + 2NH₄Cl (aq) → CaCl₂ (aq) + 2NH₃ (g) + 2H₂O (l)

Ca²⁺ + 2OH⁻ + 2NH₄⁺ + 2Cl⁻ → Ca⁺² + 2Cl⁻ + 2NH₃ (g) + 2H₂O (l)

2OH⁻ + 2NH₄⁺ → 2NH₃ (g) + 2H₂O (l)

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How does 2 Na (s) + Cl2 (g) = NaCl (s) represent the coefficient in the chemical equation
Elenna [48]

Answer:

The 2 would be placed in front of the reactant Na and in front of the product NaCl

2Na + Cl2 = 2NaCl

Explanation:

This is because the ratio of elements needs to be balanced on both sides.

On the reactants side, there are 2 Na molecules and 2 Cl molecules

On the products side, there are 2 Na molecules and 2 Cl molecules

So, now the equation is balanced

3 0
2 years ago
Consider the first-order reaction shown here. the yellow spheres in the pictures to the right represent the reactant,
Luda [366]
The rate constant of the reaction K we can get it from this formula:

K=㏑2/ t1/2 and when we have this given (missing in question):
that we have one jar is labeled t = 0 S and has 16 yellow spheres inside and the jar beside it labeled t= 10 and has 8 yellow spheres and 8 blue spheres and the yellow spheres represent the reactants A and the blue represent the products B

So when after 10 s  and we were having 16 yellow spheres as reactants and becomes 8 yellow and 8 blue spheres as products so it decays to the half amount so we can consider T1/2 = 10 s
a) by substitution in K formula:
∴ K = ㏑2 / 10 = 0.069 
The amount of A (the reactants) after N half lives = Ao / 2^n
b) so no.of yellow spheres after 20 s (2 half-lives) =  16/2^2 = 4
and the blue spheres = Ao - no.of yellow spheres left = 16 - 4 = 12
c) The no.of yellow spheres after 30 s (3 half-lives) = 16/2^3 = 2
and the blue spheres = 16 - 2 = 14

8 0
3 years ago
Which of the following is a physical property of water?
Kamila [148]
Water is NOT flammable.
6 0
3 years ago
¿Podría predecir con antelación si una disolución acuosa será buena conductora de la corriente eléctrica, sabiendo cuál es el so
Ne4ueva [31]

Answer:

Si.

Explicación:

Sí, podemos predecir si una solución acuosa será un buen conductor de corriente eléctrica si conocemos el soluto que se disuelve en ese líquido y su concentración o cantidad. Hay algunas sustancias que se ionizan cuando se agregan en un líquido como el agua. Debido a esta ionización, será un buen conductor de electricidad. Por ejemplo, la adición de una gran cantidad de cloruro de sodio en agua ioniza y hace que el agua sea un buen medio conductor de electricidad.

3 0
3 years ago
Pls help me its science
weeeeeb [17]

Answer: solids were liquds the form changes but it is still the same thing

Explanation:

7 0
2 years ago
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