Answer:
1.68 × 10²³ Molecules
Explanation:
As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (molecules) contained by 0.280 moles of Br₂, we will use following relation,
Moles = Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹
Solving for Number of Molecules,
Number of Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹
Putting values,
Number of Molecules = 0.280 mol × 6.022 × 10²³ Molecules.mol⁻¹
Number of Molecules = 1.68 × 10²³ Molecules
Hence,
There are 1.68 × 10²³ Molecules present in 0.280 moles of Br₂.
Answer:
There are 8 valence electrons
Explanation:
Answer:
a) 
and 
b) 
and 
c) 
and 
Explanation:
Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like 
, 
and 
These units of temperature are inter convertible.
a) 68°F (a pleasant spring day) to °C and K.
Converting this unit of temperature into and by using conversion factor:
b) 164°C (the boiling point of methane, the main component of natural gas) to K and °F
Conversion from degree Celsius to Kelvins and Fahrenheit
c) 0K (absolute zero, theoretically the coldest possible temperature) to °C and °F.
Answer:
B I think I am pretty sure
Answer:
volume is 7.0 liters
Explanation:
We are given;
- Molarity of the aqueous solution as 2.0 M
- Moles of the solute, K₂S as 14 moles
We are required to determine the volume of the solution;
We need to know that;
Molarity = Moles ÷ volume
Therefore;
Volume = Moles ÷ Molarity
Thus;
Volume of the solution = 14 moles ÷ 2.0 M
= 7.0 L
Hence, the volume of the molar solution is 7.0 L
