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zheka24 [161]
3 years ago
9

2.5 moles of oxygen react with 3.5 moles of hydrogen according to the following balance equation: 2H2 + 1 O2 —> 2 H2O. What i

s the ratio of limiting reactant started with/limiting reactant needed?
Chemistry
1 answer:
mash [69]3 years ago
3 0

Answer:

limiting reactant started with/limiting reactant needed=

= 3.5 mol/3.5 mol=1:1

Explanation:

                                       2H2 +   1 O2 ---> 2 H2O

from reaction                 2 mol      1 mol

given                              3.5 mol    2.5 mol

needed                          3.5 mol    1.75 mol

Excess reactant O2, Limiting reactant H2.

Limiting reactant will be used completely.

So,  limiting reactant started with/limiting reactant needed=

= 3.5 mol/3.5 mol=1:1

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Some fertilizer blends contain magnesium nitrate (MgNO3). Suppose that a chemist has 1.24 liters of a 2.13 M solution of magnesi
tamaranim1 [39]

Initial concentration of magnesium nitrate M1 = 2.13 M

Initial volume of magnesium nitrate, MgNO3  V1 = 1.24 L

Final concentration of MgNO3, M2 = 1.60 M

Let the final volume of MgNO3 upon dilution be V2

Formula to use:

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3 years ago
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3 years ago
A 100.0mL bubble of hot gases at 225 C and 1.80 atm escapes from an active volcano, what is the new volume of the bubble outside
Inessa05 [86]
<h3>Answer:</h3>

112.08 mL

<h3>Explanation:</h3>

From the question we are given;

  • Initial volume, V1 = 100.0 mL
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thus, T1 = 498.15 K

  • Initial pressure, P1 = 1.80 atm
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Rearranging the formula;

V2=\frac{P1V1T2}{T1P2}

Therefore;

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V2=112.08mL

Therefore, the new volume of the gas is 112.08 mL

8 0
3 years ago
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