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Nesterboy [21]
3 years ago
14

2. Why was it important to examine both the color and the streak of your minerals? Think about streak and explain why it’s calle

d a mineral’s “true color”. Answer in at least 2 sentences.
Chemistry
1 answer:
Delicious77 [7]3 years ago
8 0
It is important to examine both the colour and the streak of a mineral because the streak may be completely different from the colour of the hand specimen.
The streak of a mineral is the color it possesses after it has been grounded to a fine powder. The streak test has to be done on minerals because it is a more reliable way of identifying a mineral with its color.<span />
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Help me plsss
Yuki888 [10]

Answer:

8.34

Explanation:

1) how much moles of NH₃ are in the reaction;

2) how much moles of H₂ are in the reaction;

3)  the required mass of the H₂.

all the details are in the attachment; the answer is marked with red colour.

Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.

Note2: the suggested solution is not the shortest one.

8 0
3 years ago
AL(OH)3+ HCI—&gt; ALCL3 +H2O
UkoKoshka [18]

Answer:

i dont know what you're asking here. But if you're asking what it is then:

Explanation:

Aluminum Hydroxide + Hydrogen Chloride = Aluminum Chloride + Water

Al and Oh3: Aluminum Hydroxide

H and Cl: Hydrogen Chloride

Al and Cl3: Aluminum Chloride

H2O: water

btw the first letter of every element should be capitalized. While the second and theird are lowercased.

4 0
3 years ago
What is the meaning of semipermeability?​
ollegr [7]

Answer:

semipermeability

Explanation:

partially but not freely or wholly permeable specifically : permeable to some usually small molecules but not to other usually larger particles a semipermeable membrane.

8 0
3 years ago
In which environment would primary succession occur?
taurus [48]

Answer:

an area of exposed rock after a glacier melts away

Explanation:

i took the test

3 0
3 years ago
Read 2 more answers
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
4 years ago
Read 2 more answers
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