Answer:
a) a = 6.1 m/s^2
b) a = 0.98m/s^2
Explanation:
Mass of slab = 40kg
Mass of block = 10kg
Coefficient of static friction (Us) = 0.60
Kinetic coefficient (UK) = 0.40
Horizontal force = 100N
The normal reaction from 40kg slab on 10 kg block = 10*9.81
= 98.1N
Static frictional force = Us*R
= 98.1*0.6
= 58.86N
This is less than the force applied
If 10 kg block will slide on the 40 kg slab, net force = 100 - kinetic force
Kinetic force (Uk*R) = 0.4*98.1
= 39.28N
= 39N
Net force = 100 -39
= 61N
Recall that F = ma
For 10 kg block
a = F/m
a = 61/10
a = 6.1m/s^2
b) Frictional force on 40 kg slab by 10 kg = 98.1*0.4
= 39.24
= 39N
F = ma
a = F/m
For 40kg slab
a = 39/40
a = 0.98m/s^2
From the definition of apparent magnitude, we know that:
where:
m = apparent magnitude
F = corresponding flux
We also know that the flux is given by the formula:
where:
L = luminosity
d = distance
Therefore:
Now, let's apply these formulae to the same star (therefore, same luminosity), using apparent magnitude and absolute magnitude (which is defined as the apparent magnitude the star would have if it were at a distance of 10pc):
Now, let's solve for m:
= <span>
</span>
= 13
Hence,
the apparent magnitude of the star would be m = +13
Shelli will most likely say that the sound produced by the resonance of a metal is affected by the frequency at which the metal is vibrated. There is a certain frequency that will create a dim sound. If the frequency is changed to the right setting, the sound will intensify.
Answer:
356.33 J
Explanation:
Energy: This can be defined as the ability or the capacity to do work. The S.I unit of Energy is Joules (J).
The Energy stored in a capacitor = 1/2CV²
E = 1/2CV².............................. Equation 1.
Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = potential difference across the plates of the capacitor.
Given: C = 10.5 μF = 10.5×10⁻⁶ F, V = 8250 V.
Substitute into equation 1
E = 1/2(10.5×10⁻⁶)(8250)²
E = 357.33 J.
Thus the energy stored in the defibrillator = 356.33 J
