Answer:
i think answer should be C
The velocity is 6.75
The velocity in the equation stated above can be calculated as follows
m= 2,000
p= 2.25
y= 6000
velocity= 2.25 × 6000/ 2000
= 13500/2000
= 6.75
Hence the velocity is 6.75
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Answer:
A) 10 m/s
Explanation:
We know that according to conservation of momentum,
m1v1 + m2v2 = m1u1 + m2u2 ..............(equation 1)
where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.
From the given data
If truck and car are two bodies
truck : m1 = 2000 Kg v1 = 5 m/s u1 = 0
car : m2 = 1000 kg v2 = 0 u2 = ?
final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.
substituting the values in equation 1, we get
(2000 x 5) + 0 = 0 + (1000 x u2)
u2 =
x 5
= 10 m/s
Hence after collision, car moves at a velocity of 10 m/s
Answer:
B. When the ball is released, the thrower's arm transfers its energy to the ball.