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inessss [21]
2 years ago
12

An electric current in a conductor varies with time according to the expression I(t) = 100 sin (120πt) , where I is in amperes a

nd t is in seconds. What is the total charge passing a given point in the conductor from t = 0 to t = 1/240 s ?
Physics
1 answer:
Mice21 [21]2 years ago
7 0

The  total charge passing a given point in the conductor from t = 0 to t = 1/240 s is 12000π Coulombs

<h3>Total charge through a conductor</h3>

A conductor is a substance that allow current and electricity to pass through it.

The expression that will be used to calculate the current is expressed s:

I(t) = 100 sin (120πt)

where

I is in amperes and t is in seconds.

Since dQ = Idt =  I(t) = 100 sin (120πt)

On integrating

Q = 100*120πcos(120πt) |¹/¹²⁴⁰₀

Substitute the limits

Q = 100 * 120π

Q = 12000π Coulombs

Hence the  total charge passing a given point in the conductor from t = 0 to t = 1/240 s is 12000π Coulombs

Learn more on total charge through a conductor here: brainly.com/question/15083960

#SPJ4

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3 years ago
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A 6,000N is applied to a formula one car that weighs 500kg. What is the car's acceleration?
Vesna [10]

Answer:

<h2>12 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

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f = 6000 N

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We have the final answer as

<h3>12 m/s²</h3>

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3 years ago
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8 0
2 years ago
An automobile with a tangential speed of 54.1 km/h follows a circular road that has a radius of 41.6 m. The automobile has a mas
Viefleur [7K]

1) Available force of friction: 6174 N

2) No

Explanation:

1)

The magnitude of the frictional force between the car's tires and the pavement of the road is given by

F_f=\mu mg

where

\mu is the coefficient of friction

m is the mass of the car

g is the acceleration of gravity

For the car in this problem, we have:

\mu=0.500 (coefficient of friction)

m = 1260 kg (mass of the car)

g=9.8 m/s^2

Therefore, the force of friction is

F_f=(0.500)(1260)(9.8)=6174 N

2)

In order to mantain the car in circular motion, the force of friction must be at least equal to the centripetal force.

The centripetal force is given by

F=m\frac{v^2}{r}

where

m is the mass of the car

v is the tangential speed

r is the radius of the curve

In this problem, we have

m = 1260 kg

v=54.1 km/h =15.0 m/s is the tangential speed

r = 41.6 m is the radius of the curve

Therefore, the centripetal force is

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4 0
4 years ago
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