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3 years ago

Help please lol, timed test

Physics

2 answers:

joja [24]3 years ago

7 0

Answer:

Explanation:

allsm [11]3 years ago

5 0

Answer:

Explanation:

i think

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I Need Assistance With This Equation:

nikklg [1K]

Check the picture below.

now, for 6 triangles, well, simply 6*6.

8 0

4 years ago

What happens when a vector is multiplied by a scalar?

iogann1982 [59]

The scalar operates only on the magnitude of the vector.
So the length of the vector may change ... becoming longer
or shorter ... but its direction doesn't change.

3 0

4 years ago

A water pipe is inclined 40.0° below the horizontal. The radius of the pipe at the upper end is 2.00 cm. If the gauge pressure a

aliya0001 [1]

Answer:

$P_2 = -1.9 \times 10^8 Pa$

Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

$Q = A_1v_1 = A_2v_2$

at the upper end the area is given as

$A_1 = \pi r_1^2$

$A_1 = \pi(0.02)^2 = 1.26 \times 10^{-3} cm^2$

Also at the other end

$A_2 = \pi r_2^2$

$A_2 = \pi(0.01)^2 = 0.314 \times 10^{-3} cm^2$

now the speed at two ends is given as

$v_1 = \frac{20}{1.26 \times 10^{-3}}$

$v_1 = 159.15 m/s$

$v_2 = \frac{20}{0.314 \times 10^{-3}}$

$v_2 = 637 m/s$

now by Bernoulli's theorem we have

$P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2$

now we have

$0.112(1.013 \times 10^5) + \frac{1}{2}1000(159.15)^2 + 1000(9.81)(2.65sin40) = P_2 + \frac{1}{2}(1000)(637)^2 + 0$

Now we have

$P_2 = -1.9 \times 10^8 Pa$

4 0

3 years ago

Un vagón de carga de 5000-kg se mueve a 2m/s e impacta a un vagón de 10000-kg que se encuentra en reposo. Después de la colisión

Mariulka [41]

Answer:

0.67 m/s

Explanation:

Mass of car 1, m₁ = 5000 kg

Mass of car 2, m₂ = 10,000 kg

Initial speed of car 1, u₁ = 2 m/s

Final speed of car 2, u₂ = 0 (at rest)

We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.

$m_1u_1+m_2u_2=(m_1+m_2)V\\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{5000\times 2}{(5000+10000)}\\\\V=0.67\ m/s$

So, after the inelastic collision, they will move with a speed of 0.67 m/s.

6 0

3 years ago

the face of a cube towards A is brightly and shiny and the face towards V is full black.State with reason the adjustments that s

MariettaO [177]

Explanation:

increase the distance of cube from black and dull substance

5 0

3 years ago