Question

Please help

Answer 1

Explanation:

Hello, let's observe the given data first. The data says The conc of magnesium chloride solution is 0.117 mol/L that means in one litre solution 0.117 mole MgCl2 are present. but we have to find the moles of magnesium chloride, magnesium ions & chloride ions in 16.4 mL solution.

$\sf \: 1 \: litre \: solution \rightarrow 0.117 \: mole \: MgCl_2$

$\sf \: 16.4 \: millitre \: solution \rightarrow 0.117 \times \frac{16.4}{ {10}^{3} } \: mole \: MgCl_2 \\ \boxed{\sf 1.91 \times {10}^{ - 3} \: mole \: MgCl_2}$

Now 16.4 ml solution contains 1.91× 10-³ magnesium chloride.

Before finding the amount of ions in solution let's have a look at dissociation of magnesium chloride.

$MgCl_2 \rightarrow Mg^{2+} + 2Cl^{-}$

One mole of Magnesium chloride produces 1 mole of magnesium & 2 mole of chloride ions.

Hence 1.91× 10-³ moles of magnesium chloride will produce 1.91 × 10-³ moles of magnesium ion & 3.82 × 10-³ moles of chloride ions.

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