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2 years ago

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Chemistry

1 answer:

ozzi2 years ago

3 0

Answer:

For more information about each chemical, view the safety data sheets. Click the Product Resources tab followed by Datasheet. You’ll need these materials: test tube rack test tubes (quantity: 6) test tube labels graduated cylinder wash bottle with distilled water (Tap water is acceptable, but it can skew the experimental results.) pipettes (quantity: 2) forceps 50-milliliter Erlenmeyer ask scoop test tube brush apron goggles gloves pen or re-tip marker small piece of sandpaper chemicals from Edmentum Lab kit: copper metal strip (quantity: 1) iron nails (quantity: 2) zinc metal strips (quantity: 3) copper(II) sulfate solution (10 milliliters) iron(III) nitrate solution (10 milliliters), also called ferric nitrate magnesium sulfate solution (10 milliliters) hydrochloric acid (30 milliliters) sodium bicarbonate (7.5 grams

Hope this helps

Explanation:

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The reaction below is at equilibrium. What would happen if more carbon were

schepotkina [342]

Explanation:

$C_{(s)} + O_{2(g)} \rightleftharpoons CO_{2(g)}$

According to le ch-atelier's principle when a chemical reaction at equilibrium subjected to any stress, then the equilibrium shifts in that direction in which effect of stress is reduced.

When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.

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5 0

1 year ago

Someone please answer the question attached.

nikdorinn [45]

Answer:

Option ( 1 )

Explanation:

This atom has a cub close pack structure, and therefore - the number of edge center present in X atoms = 4,

Number of unit cells present in X atoms = 6

____________________________________________________

Now the 6th coordination number of X atom = 6 * 4 = 24,

So respectively, the 3rd coordination number of X = 8 -

And thus the ratio between the 6th coordination number and the 3rd coordination number = 24 / 8 = 3,

Option ( 1 )

Hope that helps!

5 0

2 years ago

Calculate the volume occupied by 272g

cupoosta [38]

The answer for the following problem is mentioned below.

Therefore volume occupied by methane gas is 184.78 × 10^-3 liters

Explanation:

Given:

mass of methane( $CH_{4}$ ) = 272 grams

pressure (P) = 250 k Pa =250×10^3 Pa

temperature(t) = 54°C =54 + 273 = 327 K

Also given:

R = 8.31JK-1 mol-1 ,

Molar mass of methane( $CH_{4}$ ) = 16.0 grams

We know;

According to the ideal gas equation,

P × V = n × R × T

here,

n = m÷M

n =272 ÷ 16

n = 17 moles

Therefore,

250×10^3 × V = 17 × 8.31 × 327

V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

V = 184.78 × 10^-3 liters

Therefore volume occupied by methane gas is 184.78 × 10^-3 liters

6 0

2 years ago

Chemical formula name for V2(SO2)3 (aq) explain why

goldenfox [79]

This is the chemical doula for salt which is a polyatomic anion very prevalent in out daily lives e.g.

Salts, acid derivatives, and peroxides of sulfate are widely used in industry.

3 0

2 years ago

A buret was improperly read to 1 decimal place giving a reading of 27.2 mL. If the actual volume is 27.26 mL, what is the percen

Elenna [48]

Using the significant figure it would be 27.3

8 0

2 years ago