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Vitek1552 [10]
3 years ago
6

Find the angle between forces of 41 pounds and 68 pounds given a magnitude of 87 pounds for the resultant force. (Hint: Write fo

rce one as a vector in the direction of the positive x-axis and force two as a vector at an angle θ with the positive x-axis.)
Physics
1 answer:
dedylja [7]3 years ago
7 0

Answer:

\theta = 76.9 degree

Explanation:

As we know that the resultant of two vectors is given as

R = \sqrt{F_1^2 + F_2^2 + 2F_1 F_2 cos\theta

here we know that

R = 87 Lb

F_1 = 41 Lb

F_2 = 68 Lb

now we have

87 = \sqrt{41^2 + 68^2 + 2(41)(68)cos\theta

87^2 = 6305 + 5576 cos\theta

\theta = cos^{-1}(\frac{1264}{5576})

\theta = 76.9 degree

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a fast humvee drove from desert a to desert b. for the 12 hours, it travelled at an speed of 185 km/h. for the next 13 hours, it
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8 0
3 years ago
How much heat must be added to make a 5g substance with a specific heat of 2 J/gC that has its temperature go up 10 degrees? Q =
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Answer:

100 Joule

Explanation:

Amount of heat in agiven body is given by Q = m•C•ΔT

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ΔT is the change in the temperature of body

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coming back to problem

m = 5g

C = 2J/gC

since, it is given that temperature of body increases by 10 degrees, thus

ΔT = 10 degrees

Using the formula for heat as given

Q = m•C•ΔT

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3 years ago
How much heat is needed to melt 13.74 kg of silver that is initially at 20°C?
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Answer:

Q = 4.63 \times 10^6 J

Explanation:

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specific heat capacity of silver is given as

s = 240 J/kg C

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Q = 4.63 \times 10^6 J

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3 years ago
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