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Elena-2011 [213]
3 years ago
7

A person on a roof throws one ball downward and an identical ball upward at the same speed. The ball thrown downward hits the gr

ound with 100 J of kinetic energy.
Ignoring air friction, with how much kinetic energy does the second ball hit the ground?

A) 200 J

B) 100 J

C) Less than 100 J

D) More than 200 J

E) none of the above
Physics
1 answer:
Alisiya [41]3 years ago
6 0

Answer:C

Explanation:

Given

Both ball are thrown simultaneously with same velocity

Suppose h be the height of roof and u be the initial velocity of balls

For ball thrown from room initial total energy is

E_1=Potential\ Energy\ +\ kinetic\ energy

E_1=mgh+\frac{1}{2}mu^2

Now this ball potential energy convert to kinetic energy and add up in available kinetic energy to give 100 J at bottom

For second ball, energy at bottom is equal to kinetic Energy of ball

Therefore this energy remains constant and only converts to Potential Energy as ball moves upward

but as soon as ball hit the ground energy will be less than 100 J because first ball has sum of Potential and Kinetic energy .

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The force required to pull the two hemispheres is 46622.72N

<h3>Calculation and Parameters</h3>

( Note: 1 millibar=100 N/m2. One atmosphere is 1013 millibar = 1.013×105 N/m2 ]

The contact area between the hemispheres is (pi x 0.400^2) = 0.5024m^2.

Pressure difference = (940 - 12)

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(928 x 100)

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Therefore, the required force to pull the two hemispheres is

(92800 x 0.5024)

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1 year ago
Why don’t we feel the gravitational force of a large object such as a skyscraper semi-truck?
Kobotan [32]

Answer:

Se the explanation below

Explanation:

We do not feel these forces of these bodies, because they are very small compared to the force of Earth's attraction. Although its mass is greater than that of a human being, its mass is not compared to the Earth's mass. In order to understand this problem we will use numerical data and the universal gravitation formula, to give validity to the explanation.

<u>Force exerted by the Earth on a human being</u>

<u />

F=G*\frac{m_{1}*m_{2}}{r^2}

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 5.97*10^24[kg]

r = distance from the center of the earth to the surface or earth radius = 6371 *10^3 [m]

<u />

Now replacing we have

F = 6.673*10^{-11} *\frac{80*5.97*10^{24}}{(6371*10^{3})^{2}  } \\F = 785[N]

<u>Force exerted by a building on a human being</u>

<u />

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 300000 [ton] = 300 *10^6[kg]

r = distance from the building to the person = 2[m]

F = 6.673*10^{-11}*\frac{80*300*10^6}{2^{2} }  \\F= 0.4 [N]

As we can see the force exerted by the Earth is 2000 times greater than that exerted by a building with the proposed data.

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3 years ago
Every sample of a pure substance has exactly the same composition and the same properties. true or false
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Answer:

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