6.6 miles I think hope this is the right answer.
So, <u>the acceleration of the car is -1</u><u>.</u><u>25 m/s²</u>. In other word, the car is also decelerating by 1.25 m/s².
<h2>Introduction</h2>
Hi ! I will help you to discuss about "deceleration in a straight line movement". Please note in advance that deceleration is acceleration which has a negative value. <u>When an object decelerates, the object will continue to move until it reaches a certain speed (which is less than before) or until it stops</u>. The higher the deceleration value, an object that is moving will stop faster and cover a shorter distance.
<h3>Formula Used</h3>
In this opportunity, I will give you the following equation to express the relationship between final velocity and initial velocity, acceleration, and distance.
With the following condition:
- = final velocity of an object (m/s)
- = initial velocity of an object (m/s)
- a = acceleration that happen (m/s²)
- s = the shift or distance of the object (m)
<h3>Problem Solving </h3>
We know that:
- = initial velocity of an object = 72 km/h = 20 m/s
- = final velocity of an object = 54 km/h = 15 m/s
- s = the shift or distance of the object = 70 m
Note :
- 1 m/s = 3.6 km/h. So 10 m/s = 36 km/h
What was asked ?
- a = acceleration that happen = ... m/s²
Step by step :
<h3>Conclusion </h3>
Here, we see that the acceleration is -1.25 m/s². In other words, the car is also decelerating by 1.25 m/s².
Answer:
Option (B)
Explanation:
According to Hubble's law, the distance from the earth to the distant galaxies is directly proportional to their recessional velocity (redshift). This means that the more is the distance between the earth and a galaxy, the faster the galaxy is moving away from the earth.
Recessional velocity normally refers to the speed or velocity at which any astronomical body such as a planet, asteroid, star or galaxy moves away from a reference point, such as from earth.
Thus, the correct answer is option (B).
Answer:
Yes
Explanation:
This helps youngsters be empathetic citizens