Fusion is a type of ____

How is Newtons second law apply to the egg drop ?

kotykmax [81]

Answer:

Newton's Second Law is applied because of the acceleration caused by natural forces as the egg is plummeting to the earth. And the amount of acceleration the egg has will be largely affected by the amount of force Mr. Baker uses to hurl the egg to the ground.

Explanation:

hope that helps

3 0

3 years ago

A baseball player hits a homerun, and the ball lands in the left field seats, which is 103m away from the point at which the bal

Sati [7]

(a) The ball has a final velocity vector

$\mathbf v_f=v_{x,f}\,\mathbf i+v_{y,f}\,\mathbf j$

with horizontal and vertical components, respectively,

$v_{x,f}=\left(20.5\dfrac{\rm m}{\rm s}\right)\cos(-38^\circ)\approx16.2\dfrac{\rm m}{\rm s}$

$v_{y,f}=\left(20.5\dfrac{\rm m}{\rm s}\right)\sin(-38^\circ)\approx-12.6\dfrac{\rm m}{\rm s}$

The horizontal component of the ball's velocity is constant throughout its trajectory, so $v_{x,i}=v_{x,f}$ , and the horizontal distance x that it covers after time t is

$x=v_{x,i}t=v_{x,f}t$

It lands 103 m away from where it's hit, so we can determine the time it it spends in the air:

$103\,\mathrm m=\left(16.2\dfrac{\rm m}{\rm s}\right)t\implies t\approx6.38\,\mathrm s$

The vertical component of the ball's velocity at time t is

$v_{y,f}=v_{y,i}-gt$

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for the vertical component of the initial velocity:

$-12.6\dfrac{\rm m}{\rm s}=v_{y,i}-\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(6.38\,\mathrm s)\implies v_{y,i}\approx49.9\dfrac{\rm m}{\rm s}$

So, the initial velocity vector is

$\mathbf v_i=v_{x,i}\,\mathbf i+v_{y,i}\,\mathbf j=\left(16.2\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(49.9\dfrac{\rm m}{\rm s}\right)\,\mathbf j$

which carries an initial speed of

$\|\mathbf v_i\|=\sqrt{{v_{x,i}}^2+{v_{y,i}}^2}\approx\boxed{52.4\dfrac{\rm m}{\rm s}}$

and direction θ such that

$\tan\theta=\dfrac{v_{y,i}}{v_{x,i}}\implies\theta\approx\boxed{72.0^\circ}$

(b) I assume you're supposed to find the height of the ball when it lands in the seats. The ball's height y at time t is

$y=v_{y,i}t-\dfrac12gt^2$

so that when it lands in the seats at t ≈ 6.38 s, it has a height of

$y=\left(49.9\dfrac{\rm m}{\rm s}\right)(6.38\,\mathrm s)-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(6.38\,\mathrm s)^2\approx\boxed{119\,\mathrm m}$

6 0

4 years ago

A lighter-than-air balloon and its load of passengers and ballast are floating stationary above the earth. ballast is weight (of

Natali5045456 [20]

Step 1: Find the upward acceleration.
d = 107 m
a = ???
vi = 0
t = 14.4 sec
d = vi * t + 1/2 at^2
107 = 1/2 a * 14.4^2
a = 214 / (14.4)^2
a = 1.03 m/s^2
Step 2: Find the Volume of the balloon and from that the mass.

V = 4/3 * pi * r^3
r = 6.52 m
V = 4/3 x pi x 6.52^3
V= 1,161 m^3.
Density of air = m/V 1.29 = m/ 1161
M = 1.29 x 1161
m = 1498 kg
Step 3: The force keeping this in equilibrium = F = m* g
F = 1498 * 9.81 = 14692 N
Step 4: Find the mass needed to cause the upward acceleration.
14692 = (1498 - x) * (9.81 + 1.03)
14692 = (1498 - x) * 10.84 Divide both sides by 10.84
1355.35 = 1022 - x
1355.35 - 1022
x = 333.35 kg

7 0

3 years ago

Select the phrases that correctly describe density. Select one or more: a. Density is a physical property. b. Density determines

Serga [27]

Answer:

Options (A), (B), (D), and (E).

Explanation:

Density is a physical property that describes the relationship between mass and volume. This property shows whether an object will float or it will get sink. The density of substances changes with the changing temperature, as both are inversely proportional to each other.

Mathematically, density can be written as,

Density = $\frac{mass}{volume}$