Question

Given that the molar mass of NaNO3 is 85.00 g/mol, what mass of NaNO3 is needed to make 4.50 L of a 1.50 M NaNO3 solution?

Answer 1

Mass = molarity x molar mass( NaNO₃) x volume

mass = 1.50 x 85.00 x 4.50

mass = 573.75 g of NaNO₃

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Answer 2

Answer:

D.) 547 g

Explanation:

this is the right answer on edg 2020, just took quiz

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