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3 years ago

Given that the molar mass of NaNO3 is 85.00 g/mol, what mass of NaNO3 is needed to make 4.50 L of a 1.50 M NaNO3 solution?

2 answers:

8 0

Mass = molarity x molar mass( NaNO₃) x volume

mass = 1.50 x 85.00 x 4.50

mass = 573.75 g of NaNO₃

hope this helps!

Fynjy0 [20]3 years ago

4 0

Answer:

D.) 547 g

Explanation:

this is the right answer on edg 2020, just took quiz

hope this helps!!!

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What method is used to removed the unreacted copper (II) carbonate?

Evgen [1.6K]

Answer:

Filtration

Explanation:

Metal carbonate is insoluble, it is possible to filter off the unreacted substances leaving the desired salt solution

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3 years ago

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svlad2 [7]

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3 years ago

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Mariana [72]

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3 years ago

12. What is the volume of 0.07 mol of neon gas at STP?

scoundrel [369]

<h3>Answer:</h3>

2 L Ne

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Using Dimensional Analysis
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.07 mol Ne (g)

<u>Step 2: Identify Conversions</u>

STP - 22.4 L per mole

<u>Step 3: Convert</u>

Set up: $\displaystyle 0.07 \ mol \ Ne(\frac{22.4 \ L \ Ne}{1 \ mol \ Ne})$
Multiply: $\displaystyle 1.568 \ L \ Ne$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

1.568 L Ne ≈ 2 L Ne

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2 years ago

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mars1129 [50]

Answer:

hxuyufydufiduud

Explanation:

chdckjxxhtxgx

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2 years ago