Answer:
42 L
Explanation:
de los parámetros en la pregunta;
V1 = 358L
T1 = 152 ° C + 273 = 425 K
P1 = 470 mmHg × 1 atm / 760 mmHg = 0.6atm
V2 =?
P2 = 6 atmósferas
T2 = 500 K
P1V1 / T1 = P2V2 / T2
P1V1T2 = P2V2T1
V2 = P1V1T2 / P2T1
V2 = 0,6 × 358 × 500/6 × 425
V2 = 107400/2550
V2 = 42 L
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Explanation:
The electrical force between two objects is given by the formula as follows :
k is electrostatic constant
q₁ and q₂ are electric charges
d is distance between charges
So, the two force between two charged objects depends on the product of charges and distance between charges.
Mole fraction of Oxygen=0.381
Mole fraction of Oxygen= (range of moles of oxygen) ÷(general moles)
also, mole fraction of oxygen = (partial stress of oxygen) ÷ (total strain)
consequently , mole fraction of Oxygen= (2.31 atm)÷(2.31 atm + 3.75 atm)
= 0.381
The mole fraction may be calculated by means of dividing the variety of moles of 1 element of a solution by the entire quantity of moles of all the additives of a solution. It is cited that the sum of the mole fraction of all of the components inside the solution should be identical to 1.
Mole fraction is a unit of awareness. in the solution, the relative amount of solute and solvents are measured by way of the mole fraction and it's far represented through “X.” The mole fraction is the variety of moles of a selected aspect inside the answer divided by way of the entire range of moles in the given answer.
Mole fraction is the ratio between the moles of a constituent and the sum of moles of all ingredients in a mixture. Mass fraction is the ratio between the mass of a constituent and the full mass of a mixture.
The question is incomplete. Please read below to find the missing content.
Assuming that only the listed gases are present, what would the mole fraction of oxygen gas be for each of the following situations? A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.
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