Time = (distance) / (speed)
<em></em>
Time = (450 km) / (100 m/s)
Time = (450,000 m) / (100 m/s)
Time = <em>4500 seconds </em>(that's 75 minutes)
Note:
This is about HALF the speed of the passenger jet you fly in when you go to visit Grandma for Christmas.
If the International Space Station flew at this speed, it would immediately go ker-PLUNK into the ocean.
The speed of the International Space Station in its orbit is more like 3,100 m/s, not 100 m/s.
Answer:19.32 m/s
Explanation:
Given
initial speed of car(u)=4.92 m/s
acceleration(a)=![3.2 m/s^2](https://tex.z-dn.net/?f=3.2%20m%2Fs%5E2)
Speed of car after 4.5 s
using equation of motion
v=u+at
![v=4.92+3.2\times 4.5=4.92+14.4](https://tex.z-dn.net/?f=v%3D4.92%2B3.2%5Ctimes%204.5%3D4.92%2B14.4)
v=19.32 m/s
Displacement of the car after 4.5 s
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
![19.32^2-4.92^2=2\times 3.2\times s](https://tex.z-dn.net/?f=19.32%5E2-4.92%5E2%3D2%5Ctimes%203.2%5Ctimes%20s)
![349.05=2\times 3.2\times s](https://tex.z-dn.net/?f=349.05%3D2%5Ctimes%203.2%5Ctimes%20s)
s=54.54 m
Answer:
B) No.
Explanation:
Okay,so,
this is equation is y=mx +b
mx represents the slope
and b represents the y-intercept
in order to figure this out you need to plot the y-intercept first
that makes its (0,-6) because the 6 is negative in the equation
4x is also equal to 4/1 since we dont know what x is
we have to do rise over run for this
you go up 4 spots on the y intercept from -6 because 4 is positive
then you go to the right 1 time because 1 is positive.
this leaves you at (1,-2)
so, (2,2) is NOT a solution
Potential difference is the work done In moving a charge from one point to another in a conductor
Answer:
Following are the responses to these question:
Explanation:
Since the
is the current of ckt which depend on the reactance which inductor that also enables the ckt and inductor resistance
for capacities
for
![\to X_{L}=wL](https://tex.z-dn.net/?f=%5Cto%20X_%7BL%7D%3DwL)
When ![w \longrightarrow 2w](https://tex.z-dn.net/?f=w%20%5Clongrightarrow%202w)
then
therefore,
remains at the same so, the maximum current remains the in same ckt.