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Kazeer [188]
1 year ago
11

Find the surface area of the figure shown. 5 cm 5 cm cm 1.5 cm 8 cm your answer​

Mathematics
1 answer:
Delicious77 [7]1 year ago
4 0

Answer:

51 cm^2

Step-by-step explanation:

the formula for area of an icoselese triangle is
A = b * h / 2
h is a line from the angle where the 5 and 5 intersect to the middle of the third line
You can find h using the pythagoran theorm with the 5 being the hypotenuse and the a being half the third line

4^2 + b^2 = 5^2
16 + b^2 = 25
b = 3, so h = 3, so now
A = 8 * 3 / 2
A = 24 / 2
A = 12 cm^2

now we have the triangle, just multiply that by 2 (top and bottom)
12 * 2 = 24

sides
8 * 1.5 = 12
5 * 1.5 * 2 = 15

now add all of it
15 + 12 + 24 = 51

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stich3 [128]
5x6 = 30 divided in half because its a triangle
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2x3 = 6

15-6 = 9
4 0
2 years ago
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Find the area of the polygon. A = __ft squared
Nataliya [291]

Answer:

28.5^2

Step-by-step explanation:

The formula is, b(base)+c(height)= b+c over 2.  b+c/2.

B=19ft in this problem.

C=38ft

Knowing this, we can further simplify.

19+38/2

Now, we add 19 and 38.

(57)

57/2= 28.5

So, the anwser is 28.5^2

8 0
2 years ago
In ΔJKL, l = 860 inches, j = 920 inches and ∠K=126°. Find ∠L, to the nearest degree.
fomenos

Answer:

26

Step-by-step explanation:

JKL= ABC,  jkl=abc

1.) use law of sines to find k.

c^{2} =a^{2} +b^{2} -2abCosC    

c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515

2.) use law of cosines to find L

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}  

plug in for b and c:  \frac{860}{sinB} =\frac{1586.225515}{sin126}

cross multiply: \frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}

sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\

L=26

5 0
3 years ago
PLEASE HELP ME -45= -2.5g
Rainbow [258]

Answer:

g=18

Step-by-step explanation:

Isolate the variables by dividing each side by -2.5.

5 0
3 years ago
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Please answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
mezya [45]

Answer:

D

Step-by-step explanation:

You have 2 5 12 13 right triangles.

x = 2 * 5

x = 10

4 0
3 years ago
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