Answer:
The answer to your question is the second option 
Step-by-step explanation:
Expression
![[\frac{(x^{2}y^{3})^{-2}}{(x^{6}y^{3}z)^{2}}]^{3}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%28x%5E%7B2%7Dy%5E%7B3%7D%29%5E%7B-2%7D%7D%7B%28x%5E%7B6%7Dy%5E%7B3%7Dz%29%5E%7B2%7D%7D%5D%5E%7B3%7D)
Process
1.- Divide the fraction in numerator and denominator
a) Numerator
[(x²y³)⁻²]³ = (x⁻⁴y⁻⁶)³ = x⁻¹²y⁻¹⁸
b) Denominator
[(x⁶y³z)²]²= (x¹²y⁶z²)³ = x³⁶y¹⁸z⁶
2.- Simplify like terms
a) x⁻¹²x⁻³⁶ = x⁻⁴⁸
b) y⁻¹⁸y⁻¹⁸= y⁻³⁶
c) z⁻⁶
3.- Write the fraction

Answer:
11 years
Step-by-step explanation:
2 years that you were in 2011
2020-2011= 9
2+9=11
also meaning they were born in 2009
2020-2009 also equals 11
this prolly doesnt make sense but hope it helps :) <3
8x(5x2+3)=8x(15+3)=8x13=104
Answer:
90
Step-by-step explanation: