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labwork [276]
1 year ago
10

You set a sensor to transmit the wind speed on top of a mountain. Which of these languages are you most likely to have used?

Engineering
1 answer:
kifflom [539]1 year ago
8 0

The programming language that is most likely used to transmit the wind speed is: B. SQL.

<h3>What is SQL?</h3>

SQL is an acronym for structured query language and it can be defined as a domain-specific programming language that is designed and developed for the management of various data that are saved in a relational or structured database.

This ultimately implies that, a structured query language (SQL) can be used to communicate with a database in accordance with the American National Standards Institute (ANSI) standards.

In conclusion, the programming language that is most likely used to transmit the wind speed is SQL.

Read more on SQL here:

brainly.com/question/25266787

#SPJ1

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At a certain location, wind is blowing steadily at 10 m/s. Determine the mechanical energy of air per unit mass and the power ge
tangare [24]

Answer:

e= 50 J/kg

Explanation:

Given that

Speed ,v= 10 m/s

Diameter of the turbine = 90 m

Density of the air ,ρ = 1.25 kg/m³

We know that mechanical energy given as

E=\dfrac{1}{2}mv^2\ J

That is why mechanical energy per unit mass will be

e=\dfrac{1}{2}v^2\ J/kg

Now by putting the values in the above equation we get

e=\dfrac{1}{2}\times 10^2\ J/kg

e= 50 J/kg

That why the mechanical energy unit mass will be 50 J/kg.

5 0
3 years ago
Which of these passages is an example of cohesive writing?
Oksana_A [137]
The answer mostly likely is: “1” due to the fact it is well ordered, and follows a similar thought process, best of luck!
3 0
2 years ago
Read 2 more answers
A steady, incompressible, two-dimensional velocity field is given by the following components in the x-y plane: u=1.85+2.05x+0.6
amm1812

1) a_x=4.287+2.772x\\a_y=-5.579+2.772y

2) 8.418

Explanation:

1)

The two components of the velocity field in x and y for the field in this problem are:

u=1.85+2.05x+0.656y

v=0.754-2.18x-2.05y

The x-component and y-component of the acceleration field can be found using the following equations:

a_x=\frac{du}{dt}+u\frac{du}{dx}+v\frac{du}{dy}

a_y=\frac{dv}{dt}+u\frac{dv}{dx}+v\frac{dv}{dy}

The derivatives in this problem are:

\frac{du}{dt}=0

\frac{dv}{dt}=0

\frac{du}{dx}=2.05

\frac{du}{dy}=0.656

\frac{dv}{dx}=-2.18

\frac{dv}{dy}=-2.05

Substituting, we find:

a_x=0+(1.85+2.05x+0.656y)(2.05)+(0.754-2.18x-2.05y)(0.656)=\\a_x=4.287+2.772x

And

a_y=0+(1.85+2.05x+0.656y)(-2.18)+(0.754-2.18x-2.05y)(-2.05)=\\a_y=-5.579+2.772y

2)

In this part of the problem, we want to find the acceleration at the point

(x,y) = (-1,5)

So we have

x = -1

y = 5

First of all, we substitute these values of x and y into the expression for the components of the acceleration field:

a_x=4.287+2.772x\\a_y=-5.579+2.772y

And so we find:

a_x=4.287+2.772(-1)=1.515\\a_y=-5.579+2.772(5)=8.281

And finally, we find the magnitude of the acceleration simply by applying Pythagorean's theorem:

a=\sqrt{a_x^2+a_y^2}=\sqrt{1.515^2+8.281^2}=8.418

4 0
3 years ago
The surface of an object is the<br> texture value appearance or function
maksim [4K]
Texture value appearance
4 0
2 years ago
The water in a soil flows from Point K to Point L, a distance of 250 ft. Point K is at elevation 543 ft and Point L is at elevat
Over [174]

Answer:

0.124

Explanation:

We calculate the hydraulic gradient by the formulas below.

I = (change in h)/(change in l)-----eqn 1

I = (hk-hl)/change in L ----- equation 2

At k the headloss = hk,

At L the headloss = hL

The distance of water travel is change in I

Total head at k

hk = 543+23

= 566 ft

Total head at L

hL = 461+74

= 535 ft

Change in L = 250

When we substitute these values in equation 2

566-535/250

= 0.124

The hydraulic gradient is 0.124

3 0
3 years ago
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